Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 15.3, Problem 23PSC
To determine

To Prove: In the given figure angle ABD is greater than Angle ABC

Expert Solution & Answer
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Explanation of Solution

Given:

  ΔBCD is isosceles with base CD¯ABD>ABC

  Geometry For Enjoyment And Challenge, Chapter 15.3, Problem 23PSC , additional homework tip  1

Formula Used:

The Hinge Theorem: It states that if two sides of two triangles are congruent and angle of one is greater than the angle of second then the third side of the triangle will be greater than the another.

Calculation:

  Geometry For Enjoyment And Challenge, Chapter 15.3, Problem 23PSC , additional homework tip  2

  In ΔABC and ΔABDBC=BDAB=ABABD>ABCAD>ACIn ΔACDACD>ADC

Conclusion:

Thus from the calculation it is proved that ACD>ADC

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