(a)
To Find: The congruent segment.
(a)
Answer to Problem 6RP
Explanation of Solution
Given:
Formula Used:
In a
Calculation:
Conclusion:
Thus the required congruent segments are
(b)
To Find: The requiredshorter segment in the given figure.
(b)
Answer to Problem 6RP
Explanation of Solution
Given:
Formula Used:
In a triangle side opposite to greater angle is always greater and opposite to smallest angel is always smallest or vice-versa.
Angle-Sum Property: In a triangle the sum of all interior angle is equal to 180.
Calculation:
Conclusion:
Thus the required segment is
(c)
To Define: The name of the required segment.
(c)
Answer to Problem 6RP
Hypotenuse
Explanation of Solution
Given:
Formula Used:
Pythagorean-Theorem: It states that in right angled triangle the longest segment is termed as Hypotenuse.
Calculation:
Conclusion:
Thus the name of required segment is Hypotenuse.
(d)
To Find: The required longer segment in the given figure.
(d)
Answer to Problem 6RP
Explanation of Solution
Given:
Formula Used:
In a triangle side opposite to greater angle is always greater and opposite to smallest angel is always smallest or vice-versa.
Angle-Sum Property: In a triangle the sum of all interior angle is equal to 180.
Calculation:
Conclusion:
Thus the required segment is
(b)
To Find: The required shortest segment in the given figure.
(b)
Answer to Problem 6RP
Explanation of Solution
Given:
Formula Used:
In a triangle side opposite to greater angle is always greater and opposite to smallest angel is always smallest or vice-versa.
Angle-Sum Property: In a triangle the sum of all interior angle is equal to 180.
Calculation:
Conclusion:
Thus the required segment is
Chapter 15 Solutions
Geometry For Enjoyment And Challenge
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- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning