Chapter 15.1, Problem 9PSB

To determine

To Find: The two numbers in which variable is between.

Answer to Problem 9PSB

  $\frac{1}{5}>x>0$

Explanation of Solution

Given:

  $\angle X<\angle Y$

Formula Used:

  $a\left(c+d\right)=ac+ad$

Calculation:

  $\begin{array}{l}\frac{1}{x}>5\\ \text{⇒}1>5x\\ \text{⇒}\frac{1}{5}>x\\ \because \text{denominator cannot be zero}\\ \therefore \frac{1}{5}>x>0\end{array}$

Conclusion:

Thus, the required restrictions is $\frac{1}{5}>x>0$ .