Chapter 15.1, Problem 4PSA

To determine

To Justify: The relation of variable with another.

Answer to Problem 4PSA

  $x\text{is nine times }z$

Explanation of Solution

Given:

  $\begin{array}{l}x\text{ is twice }y\\ y\text{is thrice }z\end{array}$

Formula Used:

  $a\left(c+d\right)=ac+ad$

Calculation:

  $\begin{array}{l}x\text{ is twice }y\\ y\text{is thrice }z\\ \text{⇒}x=2y\&y=3z\\ \text{⇒}x=3\left(3z\right)\\ \text{⇒}x=9z\end{array}$

Conclusion:

Thus, $x\text{is nine times }z$ .