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Chapter 15 Solutions
Introductory Chemistry: An Active Learning Approach
- Essential oils are concentrated liquid containing metabolites extracted from plant sources and are widely used in the production of perfumes. The structures of some of these compounds present in essential oils, along with acetone, are presented below. CH3 H2C CH H2 H3CO, CH2 CH H2C H2C CH FCH2 HO H3C CH2 Compound A MM: 164.2 g/mol Boiling Point: 254 C Compound B MM: 162.19 g/mol Boiling Point: 232 C Compound C MM: 136.24 g/mol Boiling Point: 176 C Determine the most possible boiling point of each of the compounds. Refer to the possible boiling points listed above. An equal volume of COMPOUNDS A, B and C were stored in separate beakers which were left uncovered at room temperature. 1. 2. If the three liquids were allowed to stand for about 10 minutes, which of the following will have the least amount of liquid b. What physical property is the basis of the answer? Among the three liquids, what is the most recommended ingredient of a perfume that will have the most lasting scent? а.…arrow_forward2.) What is the heat energy needed to raise the temperature of 6.63moles of ethanol CH3CH2OH from a temperature of 2.33°C to 17.5°C. [CH3CH2OH=46.07g/mol] [CCH3CH2OH=2.46J/g°C]arrow_forwardV What is the angle between two of the carbon-hydrogen bonds in the methane (CH4) molecule? 口。 X Garrow_forward
- O2N- < MeO2C 쏭 CN 노 오 HCI A HBr 0°C -CO₂Mearrow_forwardQuestion 10 of 24 Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) +2 H2 (g) → CH. (g) AH° = -74.9 kJ/mol H2 (g) + 2 C(s) + N2 (g) →2 HCN (g) AH° = 270.3 kJ/mol %3D 1 Determine the enthalpy (in kJ/mol) for +/- the reaction CH4 (g) + NH3 (g) → HCN (g) +3 H2 (g). Tap here or pull up for additional resources @ %23 2$ & 2 4. 5 6 8 Q W E T Y ab U 7.arrow_forwardWould you expect butanone, CH;COCH;CH3 where the CO is a double bond, to have a higher or lower boiling point than acetone? Explain your reasoning. Propanol, CH3CH2CH2OH, has a molar mass of 60.1 g/mol and a boiling point of 97.4°C. Use intermolecular forces to explain why propanol has a higher boiling point than butane or acetone.arrow_forward
- If the heat of combustion for theobromine is the same as caffeine (2211 kcal/mol), how much heat in kcal will be given off by combustion of 0.68 g of theobromine?arrow_forwardC₁H12 + 802(g) →→ 5CO2(g) + 6H₂O (1)arrow_forwardCalculate the standard enthalpy change of the following hydrogenation reation of ethylene (C2H2) C2H2(g) + H2(g) → C2H4(g) Using the following information at standard conditions: 2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(l) ∆H° = - 2600 kJ 2 C2H4(g) + 6 O2(g) → 4 CO2(g) + 4 H2O(l) ∆H° = - 2822 kJ 2 H2(g) + O2(g) → 2 H2O(l) ∆H° = - 572 kJarrow_forward
- Why does styrene have a higher boiling point, 145 °C, than isopropanol, 83 °C? Explain your answer by indicating the types and relative strengths of intermolecular forces present in each compound (see the line structures given below). HO styrene dipole moment = 0.13 D isopropanol dipole moment = 1.66 Darrow_forward11-62(Chemical Connections 11C) What are Freons? Why were they considered ideal compounds to use as heat-transfer agents in refrigeration systems? Give structural formulas of two Freons used for this purpose.arrow_forwardWhat is the angle between two of the carbon-hydrogen bonds in the methane (CH4) molecule? 心。 Xarrow_forward
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