Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 15, Problem 4GP
Summary Introduction
To determine: The probability of boy children for the carrier woman with the X-linked lethal allele.
Introduction: The human beings contain 23 pairs of chromosomes, of which 22 pairs of chromosomes are autosomes and 1 pair of chromosomes are sex chromosomes. The chromosomes that determine the sex of an individual is called sex chromosomes. The pair of sex chromosomes present in the males are XY and in the females are XX. The part of the genes present in the X chromosomes are said to be X- linked genes.
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A color-blind man marries a woman with normal vision whose father was color-blind. Remember that color-blindness is an X-linked recessive trait. Hint: see figure 12.7 in book.
A) What is the probability that their first child will be a color-blind daughter?
B) What is the probability that their first son will be color-blind?
A man with X-linked color blindness marries a woman with no history of color blindness in her family. The daughter of this couple marries a normal man, and their daughter also marries a normal man. What is the chance that this last couple will have a child with color blindness? If this couple has already had a child with color blindness, what is the chance that their next child will be color blind?
Can a son be a carrier for an X-linked trait? Explain.
Chapter 15 Solutions
Study Guide for Campbell Biology
Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQCh. 15 - Prob. 8IQCh. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...
Ch. 15 - Prob. 3SYKCh. 15 - Prob. 4SYKCh. 15 - Thomas Hunt Morgan firmly established the location...Ch. 15 - Prob. 2TYKCh. 15 - Sex-linked traits a. are coded for by genes...Ch. 15 - Prob. 4TYKCh. 15 - Prob. 5TYKCh. 15 - Prob. 6TYKCh. 15 - Prob. 7TYKCh. 15 - Prob. 8TYKCh. 15 - Prob. 9TYKCh. 15 - Prob. 10TYKCh. 15 - Consider three genes on the X chromosome: A, B,...Ch. 15 - Prob. 12TYKCh. 15 - Genomic imprinting a. explains cases in which the...Ch. 15 - Prob. 14TYKCh. 15 - Prob. 15TYKCh. 15 - Suppose that alleles for an X-linked character for...Ch. 15 - Some girls who fail to undergo puberty are found...Ch. 15 - Prob. 18TYKCh. 15 - The genetic event that results in Turner syndrome...Ch. 15 - Prob. 20TYKCh. 15 - Prob. 1GPCh. 15 - Prob. 2GPCh. 15 - Prob. 3GPCh. 15 - Prob. 4GPCh. 15 - Prob. 5GPCh. 15 - Red-green color blindness is caused by a...
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- A form of hemophilia is caused by a sex-linked (X-linked) recessive gene. A phenotypically normal woman whose father had hemophilia marries a man who suffers with hemophilia. What is the probability that their first daughter will have hemophilia?arrow_forwardLauren reports that she had a maternal male cousin (through a maternal aunt) and a maternal great uncle (maternal grandmother’s brother) both pass away from the same x-linked lethal condition. Both affected individuals did not have genetic testing. Lauren has a normal carrier screen for x-linked lethal conditions, which you know identifies 40% of causative mutations. If Lauren is currently pregnant with a male child, what is the chance that this child will have the condition?arrow_forwardHemophilia is another example of an X-linked disease caused when a recessive allele (Xh) is expressed. If a normal male reproduces with a heterozygous normal female, what are the expected genotypes and phenotypes? Will any of their daughters develop hemophilia?arrow_forward
- How can a female carrier of an X-linked recessive disorder have a daughter who is affected?arrow_forwardColor-blindness is an X-linked, recessive trait. If a normal-sighted woman, whose father was color-blind, marries a color-blind man, what is the probability that they will have a son who is color-blind? (use the letter “B”)arrow_forwardAs Ashley cares for her son, she notices some problems in his development. During one of the baby’s checkups, Ashley voices her concerns to the pediatrician. The pediatrician performs a series of assessments on the baby and orders a genetic workup. The genetic test results demonstrate that the baby has Duchenne muscular dystrophy, which is an X-linked recessive trait. Based on your knowledge of heredity, if the baby boy has Duchenne muscular dystrophy, then what else must be true? a. The baby’s father is a carrier of the Duchenne muscular dystrophy allele and passed along this trait to the baby. b. Duchenne muscular dystrophy is an autosomal-dominant disorder. c. Ashley is a carrier of the Duchenne muscular dystrophy allele but does not display symptoms because she has two X chromosomes, one of which is normal. d. If Ashley had a baby girl (instead of a baby boy), the baby girl would be at equal risk for having Duchenne muscular dystrophy.arrow_forward
- A human female heterozygous for X-linked trait causing red-green color blindness marries a red-green color-blind male. What is the probability of their FEMALE children having red-green color blindness?arrow_forwardA woman who is a carrier for X-linked hemophilia (she does not have the disease) marries a man who does not have hemophilia. They have a daughter, named Angela, who does not have the disease. Angela marries George, who also does not have hemophilia. Angela and George have a son named Robbie. What is the chance that Robbie will have hemophilia? O 1/4 O 1/3 O 1/2 0 1/8arrow_forwardX-linked ichthyosis is an X-linked recessive trait that manifests in part as dry, scaly skin (“ichthy-” = fish or fish like). Suppose a couple are considering having a child together. Parent A is heterozygous for the ichthyosis allele while Parent B is hemizygous negative for the ichthyosis allele. What is the probability their child would be unafflicted with ichthyosis but be a carrier of the ichthyosis-causing allele? a.0% b.25% c.50% d.75% e.100%arrow_forward
- A man with red-green color blindness marries a woman who is not color blind. They have 3 children, one of which is a color blind girl. What is the genotype of the mother? Color blindness is an X-linked trait.arrow_forwardHemophilia is an X-linked recessive disease. A hemophilic man marries a woman who is not a carrier of the disease. (a) Draw a Punnett square showing the genotypes of their children. (b) What are the chances that their daughters will be carriers of the disease? (c) What percentage of their children are likely to have the disease?arrow_forwardHemophilia, disease in which the blood lacks a clotting factor, is caused by an X linked recessive gene. Joe doe not have hemophilia and Lucille is heterozygous for the condition. What is the chance that their MALE child will have hemophilia? (Note: you are calculating the probability for their MALE children only, in other words if they have 1 male child, what is the probability that he will be born with the disease?) 0% 1/4 or 25% 2/4 or 50% 3/4 or 75% 4/4 or 100%arrow_forward
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