Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 15, Problem 10TYK
Summary Introduction
Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.
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Fragile X syndrome is an X-linked recessive Achondroplasia is an autosomal dominant trait characterized by a shortened stature. An XX individual is a carrier for Fragile X disorder and is unaffected by achondroplasia. An XY individual is not affected by Fragile X disorder and has achondroplasia.
a. What is the XX individual’s genotype
b. What is the XY individual’s genotype?
c. If the two individuals where to have children, what are the possible genotypes and phenotypes of their children? Use a Punnett square.
d. What is the probability of them having a child with Fragile X and achondroplasia?
Calico is a coat color found in cats, which is caused by a X-linked, co-dominant alleleFemale cats: XBXB= black; XOXO = orange; and XBXO = calico
Male cats: XBY = black; orange XOY = orange
What is the outcome of a black male crossed with an orange female?
A. All offspring are black
B. All female cats are calico, male cats are orange
C. All female cats are calico, male cats are orange
D. 1/4 female calico, 1/4 female black, 1/4 male black, 1/4 male orange
Choose the statement that is incorrect.a. A son can inherit a recessive allele on anX chromosome from either parent.b. An individual may inherit three or more of eachtype of chromosome characteristic of the species, acondition called polyploidy.c. A female child inherits one X chromosome from hermother and one from her father.d. Pedigree analysis can be used to determine a futurechild’s chance of being born with achondroplasia
Chapter 15 Solutions
Study Guide for Campbell Biology
Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQCh. 15 - Prob. 8IQCh. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...
Ch. 15 - Prob. 3SYKCh. 15 - Prob. 4SYKCh. 15 - Thomas Hunt Morgan firmly established the location...Ch. 15 - Prob. 2TYKCh. 15 - Sex-linked traits a. are coded for by genes...Ch. 15 - Prob. 4TYKCh. 15 - Prob. 5TYKCh. 15 - Prob. 6TYKCh. 15 - Prob. 7TYKCh. 15 - Prob. 8TYKCh. 15 - Prob. 9TYKCh. 15 - Prob. 10TYKCh. 15 - Consider three genes on the X chromosome: A, B,...Ch. 15 - Prob. 12TYKCh. 15 - Genomic imprinting a. explains cases in which the...Ch. 15 - Prob. 14TYKCh. 15 - Prob. 15TYKCh. 15 - Suppose that alleles for an X-linked character for...Ch. 15 - Some girls who fail to undergo puberty are found...Ch. 15 - Prob. 18TYKCh. 15 - The genetic event that results in Turner syndrome...Ch. 15 - Prob. 20TYKCh. 15 - Prob. 1GPCh. 15 - Prob. 2GPCh. 15 - Prob. 3GPCh. 15 - Prob. 4GPCh. 15 - Prob. 5GPCh. 15 - Red-green color blindness is caused by a...
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- In humans, the genes for coloblindedness and hemophilia re both located on the X chromosome with no corresponding gene in the Y. These are both recessive alleles. a. If a man and a woman, both with normal vision, marry and have a colorblind son, draw the Punnet square that illustrates this. b. If the man dies and the woman remarries to a colorblind man, draw a Punnet Square showing the type of children could be expected from hre second marriage. How many/what percentages of each could ne expectedarrow_forwardFragile X is a disorder which causes mental impairment in affected individuals. The trait which is due to a mutation in the FMR1 gene on the X chromosome is inherited in a recessive manner. An unaffected son was born to an affected man and an unaffected woman. The woman’s mother was affected while the father was normal. a. Indicate the gene notation. b. Give the genotype of the son. c. Is it possible for the couple to have an affected daughter? affected son? Derive the genotypic and phenotypic ratios for the offspring. Show and label your solutions properly. d. If the couple has four children, what is the probability that they will have three normal daughters and one normal son?arrow_forwardWhich of the following is an explanation for independent assortment of alleles on different chromosomes (Mendel's second law)? A. Chromosomes can have different functions in various types of cells of the same organism. B. In metaphase I, alignment of 1 pair of replicated chromosomes does not affect the alignment of another pair. C. Each chromosome is capable of a different function. D. In prophase I, which chromosomes pairs with which other one is completely random. E. Chromosomes are divided into daughter cells in a random fashion.arrow_forward
- Which of the following statements about calico cats is true? Select all that apply.arrow_forwardWebbed fingers is inherited as an X-linked disease An unaffected male marries an affected female. a. Draw a Punnett square of the possible offspring. b. List the phenotypes of the possible children c. Draw a pedigree that displays the inheritance in you Punnett squarearrow_forwardIn labrador retrievers an allele B codes for black pigment and b codes for brown. A second gene E is responsible for deposition of pigment into the hair follicle. The e allele results in the blockage of pigment deposition. a. What fraction of yellow puppies would you predict to be born in a cross between a yellow labrador Bbee and a Black labrador BbEe? b. What color is a labrador with the genotype bbEe?arrow_forward
- Tay–Sachs disease is caused by recessive alleles on anautosome. In which case(s) could two parents with anormal phenotype have a child with Tay–Sachs?a. Both parents are homozygous for a Tay–Sachs allele.b. Both parents are heterozygous for a Tay–Sachsallele.c. One parent is homozygous for a Tay–Sachs allele,and the other is heterozygous.arrow_forwardIn certain species of flies, eye color is controlled by sim-·ple dominance by a single pair of alleles. A red-eyed fly was crossed with a white-eyed fly, both of whose parents had white eyes. All of their offspring (both female and male) had red eyes.a. Which is dominant, the allele for red eyesor the allele for white eyes?b. What is the genotype of the white-eyed parents?c. If the white-eyed parent was mated with one of the red-eyed offspring, what phenotypic ratio wouldyou expect regarding eye color?arrow_forwardUnder what conditions does one expect a 9:3:3:1 ratio? What may cause this ratio to vary? A. dihybrid cross with independent assortment; epistasis B trihybrid cross with linked chromosomes; Down syndrome C dihybrid cross with linked chromosomes; the 9:3:3:1 ratio will remain unchanged regardless of other conditions D. dihybrid cross with independent assortment; Turner syndrome E. monohybrid cross with independent assortment; epistasisarrow_forward
- Due to dosage compensation by X inactivation, females can exhibit a mosaic pattern of sweat glands on only some portions of their body if they carry a particular loss of function allele. Could any of the following genotypes result in males with such a mosaic pattern of sweat glands? Explain. A. X^AY B. X^AX^AY C. X^AX^aY D. Not possiblearrow_forwardColor blindness is an X-linked trait caused by a recessive alle A carrier female marries a normal male a. How many male offspring can be expected to be color-blind and have a normal vison? b. How many female offspring can be expected to be carriers and to be normal?arrow_forwardn fruit flies, eye color is a sex-linked trait, and red eyes (the wild-type variant) are dominant to white eyes (the mutant variant denoted by the letter W). A white-eyed, male fruit fly is observed in the laboratory. The genotype of this fly is _________, which is best described as being __________. a. X+Y+; heterozygous b. XWYW; hemizygous c. XWY; homozygous recessive d. X+YW; homozygous dominant e. XWY; hemizygousarrow_forward
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