Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 15, Problem 8TYK
Summary Introduction
Introduction: Locus is the specific location of gene in a chromosome. The inheritance of two different characters is affected by the gene linkage. The production of offspring with traits that are combined is studied in recombination. Map units measure genetic linkage. Map units are calculated for linked genes.
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A cross is made between a heterozygote, +++/abc, and a recessive homozygote, abc/abc. Analysis of the progeny gave the following results:
+ + +
450
+ + C
10
a + c
70
+ b c
210
+ b +
65
a + +
200
a bc
460
ab +
15
What is the map distance between the a and c genes?
O 25.12 map units
O 27.71 map units
O 29.39 map units
O 32.53 map units
O None of the above
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In fava bean plant the seed color can be coded by two alleles, green (G) which is dominant and purple (g) which is recessive. A
gardening hobbyist performed a cross between 2 true-breeding lines P1 and P2 that respectively have green and purple seeds.
Answer the following questions in regard to the hobbyist experiment.
1) What are the genotypes of the parental lines A and B? what are the genotypes of the gametes of each parent?
2)What is the phenotype and genotype of the F1 generation of the cross?
3) What are the proportions of the genotypes of the F2 generation?
4)What are the proportions of the phenotypes of the F2 generation?
A cross is made between a heterozygote, +++/abc, and a recessive homozygote, abc/abc. Analysis of the progeny gave the following results:
450
10
a + c
70
+ b c
210
+ b +
65
a + +
200
abc
460
ab+
15
What is the map distance between the b and c genes?
O9.12 map units
O 10.81 map units
O 12.14 map units
O 13.95 map units
ONone of the above
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Chapter 15 Solutions
Study Guide for Campbell Biology
Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQCh. 15 - Prob. 8IQCh. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...
Ch. 15 - Prob. 3SYKCh. 15 - Prob. 4SYKCh. 15 - Thomas Hunt Morgan firmly established the location...Ch. 15 - Prob. 2TYKCh. 15 - Sex-linked traits a. are coded for by genes...Ch. 15 - Prob. 4TYKCh. 15 - Prob. 5TYKCh. 15 - Prob. 6TYKCh. 15 - Prob. 7TYKCh. 15 - Prob. 8TYKCh. 15 - Prob. 9TYKCh. 15 - Prob. 10TYKCh. 15 - Consider three genes on the X chromosome: A, B,...Ch. 15 - Prob. 12TYKCh. 15 - Genomic imprinting a. explains cases in which the...Ch. 15 - Prob. 14TYKCh. 15 - Prob. 15TYKCh. 15 - Suppose that alleles for an X-linked character for...Ch. 15 - Some girls who fail to undergo puberty are found...Ch. 15 - Prob. 18TYKCh. 15 - The genetic event that results in Turner syndrome...Ch. 15 - Prob. 20TYKCh. 15 - Prob. 1GPCh. 15 - Prob. 2GPCh. 15 - Prob. 3GPCh. 15 - Prob. 4GPCh. 15 - Prob. 5GPCh. 15 - Red-green color blindness is caused by a...
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- An individual has the following genotype. Gene loci (A) and (B) are 15 m.u. apart. What are the correct frequencies of some of the gametes that car be made by this individual? Bl a O A. Ab = 7.5%; AB = 42.5% B. ab = 25%; aB = 50% O C. AB = 7.5%; aB = 42.5% O D. aB = 15%; Ab = F0% E. aB = 70%; Ab = 15% Reset Selection OMark for Review What's This?arrow_forwardKernel color in wheat Red kernel color in wheat results from the interaction between two dominant alleles. With only one dominant allele, the phenotype is brown while in the absence of any dominant allele, the phenotype is white. Suppose that plants of a variety that is true breeding for red kernels are crossed with plants true breeding for white kernels. What specific type of interaction can be observed? A. duplicate dominant genes B. duplicate genes with cumulative effects C. complementary genes D. dominant epistasis (case 2)arrow_forwardIn fruit flies, you are mapping three genes in a three point cross. The mutants are hairy body (h), sepia colored eyes (se) and female sterility (g). You cross a heterozygous parent with a homozygous recessive parent and obtain the following results: Type Number h se g. 5 + se + 450 + se g 27 ++g_ h se + + + + h + g. h + + TOTAL is the gene in the middle and the distance in map units between se and g is Oh; 16.4 se; 7.1 Oh; 7.1 70 82 7 327 32 1000 se; 16.4arrow_forward
- . In common wheat, Triticum aestivum, kernel color is determined by multiply duplicated genes, each with an Rand an r allele. Any number of R alleles will give red, anda complete lack of R alleles will give the white phenotype.In one cross between a red pure line and a white pureline, the F2 was 6463 red and 641 white.a. How many R genes are segregating in this system?b. Show the genotypes of the parents, the F1, and the F2.c. Different F2 plants are backcrossed with the whiteparent. Give examples of genotypes that would give thefollowing progeny ratios in such backcrosses: (1) 1 red :1 white, (2) 3 red :1 white, (3) 7 red :1 white.d. What is the formula that generally relates thenumber of segregating genes to the proportion of redindividuals in the F2 in such systems?arrow_forwardIn Drosophila (fruit flies), jammed wings (J), daughterless (da), curly wings (Cy), star eyes (S), and a black body (b) are determined by genes located on the same chromosome. Gene Combination Recombination Frequency J and Cy 34.9 J and da 1.7 S and Cy 4.8 Cy and b 42.4 S and da 38 b and S 47.2 Which of the following options shows the gene sequence on this chromosome? Select one: a. b J Cy da S b. S Cy J da b c. S J da Cy b d. b J da Cy S e. J S da Cy barrow_forwardFigure 5.1 presented abbreviated pedigrees looking at the inheritance of X-linked human conditions. El Figure 5.1a initiated with a male who was color blind and had hemophilia A. The grandsons and great-grandsons of this male were either color blind and had hemophilia A, or they had neither condition. a. Which if any individuals in the G Fig. 5.1a pedigree is a double heterozygote? b. Are any of the grandsons or great-grandsons shown in the pedigree the product of recombinant type gametes? c. Do the genes responsible for color blindness and hemophilia A segregate independently? d. If you examined many pedigrees, each starting with a man who was simultaneously color blind and had hemophilia A, do you think any grandsons or great-grandsons would ever have one condition but not the other? L Figure 5.1b initiated with a male who was color blind and had hemophilia B. The grandsons of this male were either only color blind, only had hemophilia B, had both conditions, or they had neither…arrow_forward
- Assuming two independently assorting gene loci for eye color and wing length in Drosophila melanogaster. Using your own defined symbols (make sure you represent them first), identify the most probable genotypes of the parents of the following crosses in flies. Parents Offspring Brown-vestigial Brown-long Red-long Red-vestigial a. Red-long x 30 27 98 95 Red-vestigial 78 24 0 0 b. Brown-long x Brown-long c. Red-vestigial x 48 42 46 45 Brown-long d. Red-long x 45 16 139 51 Red-long e. Red-vestigial x 0 0 80 87 Red-longarrow_forwardCape parrots are found in forests in South Africa. In a study of Cape parrot genetics, biologists produced the karyotype shown from somatic cells of a female Cape parrot. A 29 B C D 30 56 R an ak on An an an 1 2 3 4 5 6 7 58 8 16 9 10 • 11 12 17 18 19 Based on the karyotype, how many chromosomes are present in the gametes of a Cape parrot? 25 26 27 28 20 21 PA 13 14 15 22 23 24 (8 Z W 29 Female Sex Chromosomes (? Submitarrow_forwardCross Cross A Cross A Cross B Cross B Phenotype F1 generation F2 generation F1 generation F2 generation Male red eyes 132 150 0 99 Female red eyes 135 295 110 101 Male white eyes 0 147 105 93 Female white eyes 0 0 0 95 Using “+” to indicate the wildtype red-eyed allele and “w” to indicate the mutant white-eyed allele, state the genotypes of the following: Wildtype red-eyed and white-eyed parental flies from cross A and cross B. Males and females from the F1 generation flies from cross A and cross B Males and females, F2 generation flies from cross A and cross B.arrow_forward
- Drosophila females heterozygous for three recessive mutations, a, b, and c , were crossed to males homozygous for all three mutations.The cross yielded the following results: in the image Q. Construct a linkage map showing the correct order of these genes and estimate the distances between them.arrow_forwardplease helparrow_forwardAnswer was wrongarrow_forward
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