Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 15, Problem 15.62SP
To determine
To draw the moment diagram by conventional method and by parts method for the beam (from right to left and left to right).
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Procedure:
1- Cartesian system, 2D3D,
type of support
2- Free body diagram
3 - Find the support reactions
4- If you find a negative
number then flip the force
5- Find the internal force
3D
∑Fx=0
∑Fy=0
∑Fz=0
∑Mx=0
∑My=0
ΣMz=0
2D
ΣFx=0
ΣFy=0
ΣMz=0
5- Use method of section
and cut the element
where you want to find
the internal force and
keep either side of the
Chapter 15 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 15 - A 14 in.-diameter aluminum rod is bent into a...Ch. 15 - 15.2 Calculate the maximum bending stress produced...Ch. 15 - A 500 -mm-long steel bar having a cross section of...Ch. 15 - 15.4 An aluminum wire has a diameter of in....Ch. 15 - 15.5 A -in.-wide by in.-thick board is bent to a...Ch. 15 - 15.6 A Douglas fir beam is in. wide and in. deep....Ch. 15 - Prob. 15.7PCh. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...
Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.I4, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.7 through 15.14, use the formula...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - For Problems 15.15 through 15.26, use the...Ch. 15 - 15.27 Draw the moment diagram by parts for the...Ch. 15 - 15.28 Draw the moment diagram by parts for the...Ch. 15 - 15.29 Draw the moment diagram by parts for the...Ch. 15 - 15.30 For the beam shown, draw the conventional...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - For Problems 15.31 through 15.43, use the...Ch. 15 - 15.49 If the elastic limit of a steel wire is...Ch. 15 - 15.50 Calculate the bending moment required to...Ch. 15 - 15.51 A 6-ft-long cantilever beam is subjected to...Ch. 15 - 15.52 A structural steel wide-flange section is...Ch. 15 - 15.53 A simply supported structural steel...Ch. 15 - 15.54 A structural steel wide-flange shape is...Ch. 15 - A solid, round simply supported steel shaft is...Ch. 15 - Using the moment-area method, check the...Ch. 15 - 15.57 A 1-in.-diameter steel bar is 25 ft long and...Ch. 15 - 15.58 A 102-mm nominal diameter standard-weight...Ch. 15 - I 5.59 Compute the maximum deflection for the...Ch. 15 - An 8-in-wide by 12-in-deep redwood timber beam...Ch. 15 - 15.61 A solid steel shaft 3 in. in diameter and 20...Ch. 15 - 15.62 For the beam shown, draw the conventional...Ch. 15 - 15.63 Rework Problem 15.62 with concentrated loads...Ch. 15 - 15.64 A solid steel shaft 3 in. in diameter and 20...Ch. 15 - 15.65 A structural steel wide-flange section is...Ch. 15 - 15.66 A 6-in.-by-10-in, hem-fir timber beam (S4S)...Ch. 15 - 15.67 A simply supported structural steel...Ch. 15 - Calculate the maximum permissible span length for...Ch. 15 - 15.69 A structural steel wide-flange section 10 ft...Ch. 15 - 15.70 A structural steel wide-flange section...Ch. 15 - 15.71 Determine the deflection at point C and...Ch. 15 - 15.72 Calculate the deflection midway between the...Ch. 15 - 15.73 Derive an expression for the maximum...Ch. 15 - 15.74 Derive an expression for the maximum...
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- Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
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