Chapter 14.2, Problem 11SP

Interpretation Introduction

Interpretation: To determine the volume if the pressure does not change.

Concept Introduction: Charles’s law talks about the relationship between volume and temperature at constant pressure. It can be expressed as,

  $\text{V}\text{=}\text{KT}$ .

Where V is volume and T is temperature.

Answer to Problem 11SP

3.38 L.

Explanation of Solution

The given data:

  ${\text{V}}_{\text{1}}$ = 6.08 mL

  ${\text{V}}_{\text{2}}$ = ?

  $\begin{array}{c}{\text{T}}_{\text{1}}\text{=}{\text{325}}^{\text{ο}}\text{C}\\ \text{=}\text{273}\text{+}\text{325}\\ \text{=}\text{598 K}\end{array}$

  $\begin{array}{c}{\text{T}}_{\text{2}}\text{=}{\text{25}}^{\text{ο}}\text{C}\\ \text{=}\text{273}\text{+}\text{25}\\ \text{=}298\text{ K}\end{array}$

The volume can be determined by using the formula:

  $\frac{{\text{V}}_{\text{1}}}{{\text{V}}_{\text{2}}}\text{=}\frac{{\text{T}}_{\text{2}}}{{\text{T}}_{\text{2}}}\mathrm{.....}\text{(i)}$

Now, put the values of the given data in equation (i).