Excursions in Modern Mathematics (9th Edition)
9th Edition
ISBN: 9780134468372
Author: Peter Tannenbaum
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 14, Problem 7E
You want to estimate how many fish there are in a small pond. Let’s suppose that you first capture
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Instructions.
"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."
Both in images okk. Instructions.
"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."
Question 1:
If a barometer were built using oil (p = 0.92 g/cm³) instead of mercury (p =
13.6 g/cm³), would the column of oil be higher than, lower than, or the same as the
column of mercury at 1.00 atm? If the level is different, by what factor? Explain. (5 pts)
Solution:
A barometer works based on the principle that the pressure exerted by the liquid column
balances atmospheric pressure. The pressure is given by:
P = pgh
Since the atmospheric pressure remains constant (P = 1.00 atm), the height of the
liquid column is inversely proportional to its density:
Step 1: Given Data
PHg
hol=hgx
Poil
• Density of mercury: PHg = 13.6 g/cm³
Density of oil: Poil = 0.92 g/cm³
• Standard height of mercury at 1.00 atm: hμg
Step 2: Compute Height of Oil
= 760 mm = 0.760 m
13.6
hoil
= 0.760 x
0.92
hoil
= 0.760 × 14.78
hoil
= 11.23 m
Step 3: Compare Heights
Since oil is less dense than mercury, the column of oil must be much taller than that of
mercury. The factor by which it is taller is:
Final…
Chapter 14 Solutions
Excursions in Modern Mathematics (9th Edition)
Ch. 14 - As part of a sixth-grade class project the teacher...Ch. 14 - As part of a sixth-grade class project the teacher...Ch. 14 - Madison County has a population of 34,522 people....Ch. 14 - Madison County has a population of 34,522 people....Ch. 14 - A big concert was held at the Bowl. Men and women...Ch. 14 - A large jar contains an unknown number of red...Ch. 14 - You want to estimate how many fish there are in a...Ch. 14 - To estimate the population in a rookery, 4965 fur...Ch. 14 - To count whale populations, the capture is done by...Ch. 14 - The critically endangered Mauis dolphin is...
Ch. 14 - Exercises 11 and 12 refer to Chapmans correction....Ch. 14 - Exercises 11 and 12 refer to Chapmans correction....Ch. 14 - Starting in 2004, a study to determine the number...Ch. 14 - Exercises 25 through 28 refer to the following...Ch. 14 - Name the sampling method that best describes each...Ch. 14 - An audit is performed on last years 15, 000...Ch. 14 - Exercise17 through 20 refer to the following...Ch. 14 - Exercise17 through 20 refer to the following...Ch. 14 - Exercise17 through 20 refer to the following...Ch. 14 - Exercise17 through 20 refer to the following...Ch. 14 - Prob. 21ECh. 14 - Prob. 22ECh. 14 - Prob. 23ECh. 14 - Prob. 24ECh. 14 - Exercises 25 through 28 refer to the following...Ch. 14 - Exercises 25 through 28 refer to the following...Ch. 14 - Exercises 25 through 28 refer to the following...Ch. 14 - Exercises 29 and 30 refer to the following story:...Ch. 14 - Exercises 29 and 30 refer to the following story:...Ch. 14 - Prob. 31ECh. 14 - Prob. 32ECh. 14 - Exercises 33 through 36 refer to the following...Ch. 14 - Exercises 33 through 36 refer to the following...Ch. 14 - Exercises 33 through 36 refer to the following...Ch. 14 - Exercises 33 through 36 refer to the following...Ch. 14 - Exercises 37 through 40 refer to a clinical study...Ch. 14 - Exercises 37 through 40 refer to a clinical study...Ch. 14 - Exercises 37 through 40 refer to a clinical study...Ch. 14 - Prob. 40ECh. 14 - Prob. 41ECh. 14 - Exercises 41 through 44 refer to a clinical trial...Ch. 14 - Prob. 43ECh. 14 - Exercises 41 through 44 refer to a clinical trial...Ch. 14 - Prob. 45ECh. 14 - Prob. 46ECh. 14 - Exercises 45 through 48 refer to a study on the...Ch. 14 - Prob. 48ECh. 14 - Exercises 49 through 52 refer to a landmark study...Ch. 14 - Prob. 50ECh. 14 - Exercises 49 through 52 refer to a landmark study...Ch. 14 - Prob. 52ECh. 14 - Exercises 53 through 56 refer to a study conducted...Ch. 14 - Prob. 54ECh. 14 - Exercises53_ through 56_ refer to a study...Ch. 14 - Exercises53 through 56 refer to a study conducted...Ch. 14 - Prob. 57ECh. 14 - Prob. 58ECh. 14 - Exercises 57 through 60 refer to the following...Ch. 14 - Prob. 60ECh. 14 - Prob. 61ECh. 14 - Prob. 62ECh. 14 - Prob. 63ECh. 14 - Prob. 64ECh. 14 - Read the examples of informal surveys given in...Ch. 14 - Leading-question bias. The way the questions in...Ch. 14 - Prob. 67ECh. 14 - Prob. 68ECh. 14 - Prob. 69ECh. 14 - Prob. 70ECh. 14 - Prob. 71ECh. 14 - Prob. 72ECh. 14 - One of the problems with the capture-recapture...Ch. 14 - Darrochs method. is a method for estimating the...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.Similar questions
- Question 3: A sealed flask at room temperature contains a mixture of neon (Ne) and nitrogen (N2) gases. Ne has a mass of 3.25 g and exerts a pressure of 48.2 torr. . N2 contributes a pressure of 142 torr. • What is the mass of the N2 in the flask? • Atomic mass of Ne = 20.1797 g/mol • Atomic mass of N = 14.0067 g/mol Solution: We will use the Ideal Gas Law to determine the number of moles of each gas and calculate the mass of N2. PV = nRT where: • P = total pressure • V volume of the flask (same for both gases) n = number of moles of gas • R 0.0821 L atm/mol K • T = Room temperature (assume 298 K) Since both gases are in the same flask, their partial pressures correspond to their mole fractions. Step 1: Convert Pressures to Atmospheres 48.2 PNe = 0.0634 atm 760 142 PN2 = = 0.1868 atm 760 Step 2: Determine Moles of Ne nNe = mass molar mass 3.25 nNe 20.1797 nne 0.1611 mol Step 3: Use Partial Pressure Ratio to Find narrow_forward"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."arrow_forwardNo chatgpt pls will upvote Already got wrong chatgpt answerarrow_forward
- Construct a table of values for all the nonprincipal Dirichlet characters mod 16.arrow_forwardMI P X /courses/segura10706/products/171960/pages/611?locale=&platformId=1030&lms=Y ☆ Finish Part I: Mathematics for Elementary and Middle School Teachers Continue in the app JJ 576 Chapter 12. Area of Shapes 9. Determine the area of the shaded shapes in Figure 12.48. Explain your reasoning. 1 unit S Figure 12.48 1 unit unit and the yarn for thearrow_forwardSuppose p > 3 is a prime. Show that (p − 3)!= − P+1 (mod p). Hint: Use Wilson's theorem.arrow_forward
- Which graph represents f(x) = √x-2+3?arrow_forwardSuppose a = p²¹...p be the canonical factorization. Then the sum of all the factors of a, denoted by σ(a) is given by o(a) = II + k₂+1 P -1 Pi - 1 (you don't need to prove this). (a) Let a = 2³ × 7². Find σ(a), which the sum of all the factors a.arrow_forwardEvaluate the Legendre symbol (999|823). (Note that 823 is prime.)arrow_forward
- If p = 7 (mod 8), where p is prime, show that p divides 2(p-1)/2 — 1. Deduce that 275 - 1 and 2155 -1 are composite.arrow_forwardSolve the simultaneous linear congruences 3x = 2 (mod 5), 3x = 4 (mod 7), 3x = 6 (mod 11).arrow_forwardcondition: Throughout this question, n is a positive integer satisfying the following (n) = 2³ × 17 × q, gcd(n,6) = 1, q = 2(mod3) is an odd prime. (a) Show that 17†n. - (b) Show that 17|(p − 1) for some prime factor p of n.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Mathematics For Machine TechnologyAdvanced MathISBN:9781337798310Author:Peterson, John.Publisher:Cengage Learning,
Algebra for College StudentsAlgebraISBN:9781285195780Author:Jerome E. Kaufmann, Karen L. SchwittersPublisher:Cengage Learning
Intermediate AlgebraAlgebraISBN:9781285195728Author:Jerome E. Kaufmann, Karen L. SchwittersPublisher:Cengage Learning
Algebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal Littell
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Mathematics For Machine Technology
Advanced Math
ISBN:9781337798310
Author:Peterson, John.
Publisher:Cengage Learning,
Algebra for College Students
Algebra
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Cengage Learning
Intermediate Algebra
Algebra
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Cengage Learning
Algebra: Structure And Method, Book 1
Algebra
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell
Finding Local Maxima and Minima by Differentiation; Author: Professor Dave Explains;https://www.youtube.com/watch?v=pvLj1s7SOtk;License: Standard YouTube License, CC-BY