Calculus: Graphical, Numerical, Algebraic

3rd Edition

ISBN: 9780133688399

Author: Finney, Ross L.

Publisher: Pearson/Prentice Hall

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Question

Chapter 1.4, Problem 1QR

To determine

To find: The equation of line passing through the points (1,8) and (4,3) .

Expert Solution & Answer

Answer to Problem 1QR

The required equation of the line is y=−53x+293 .

Explanation of Solution

Given information: The points are (1,8) and (4,3) .

Formula used: The equation of line passing through points (x1, y1) and (x2, y2) is given by,

y−y1=m(x−x1)

Here, the slope of the line is m=y2−y1x2−x1 .

Calculation:

Find the slope of the line passing through these points.

Substitute

1 for x1 , 8 for y1 , 4 for x2 and 3 for y2 in the formula m=y2−y1x2−x1 .

m=3−84−1=−53

Substitute 1 for x1 , 8 for y1 and −53 for m in the formula y−y1=m(x−x1) to find the equation of line.

y−8=−53(x−1)y−8=−53x+53y=−53x+53+8y=−53x+293

Therefore, the required equation of the line is y=−53x+293 .

Chapter 1.3, Problem 4QQ

Chapter 1.4, Problem 2QR

Chapter 1 Solutions

Calculus: Graphical, Numerical, Algebraic

Ch. 1.1 - Prob. 1QR Ch. 1.1 - Prob. 2QR Ch. 1.1 - Prob. 3QR Ch. 1.1 - Prob. 4QR Ch. 1.1 - Prob. 5QR Ch. 1.1 - Prob. 6QR Ch. 1.1 - Prob. 7QR Ch. 1.1 - Prob. 8QR Ch. 1.1 - Prob. 9QR Ch. 1.1 - Prob. 10QR

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