The steps of the biosynthetic pathway that are associated with each type of mutation from the given data. Given: Two mutant strains of Neurospora ( Leu- 1 and Leu- 2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−). Table 1: The results of the growth of different strains of Neurospora in different media. Types of strains used in the experiment The growth of different strains of Neurospora in different media Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate Wild-type (haploid) + + + + + Leu- 1 (haploid) − − + − + Leu -2 (haploid) − − + + + Fused cells (diploid): Leu -1, Leu -2 − + + + + The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1). Figure 1: Introduction: The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 14, Problem 1Q

Summary Introduction

To analyze:

The steps of the biosynthetic pathway that are associated with each type of mutation from the given data.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild-type (haploid) + + + + +

Leu-1 (haploid) − − + − +

Leu-2 (haploid) − − + + +

Fused cells (diploid): Leu-1, Leu-2 − + + + +

The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Expert Solution & Answer

Explanation of Solution

Neurospora is able to synthesize leucine in their cells and hence, are able to grow on a minimal medium (a medium that does not contain additional amino acids). The mutant strains of Neurospora lack the precursors that are required to perform the metabolic steps for the leucine synthesis. The two important mutant strains of Neurospora are Leu-1 and Leu-2.

From the given table and diagram, it is observed that Leu-1 strain contains a mutation in the protein that is required for the synthesis of α-ketoisocaproate. This is because this strain is unable to grow in the minimal medium supplied with 3-isopropylmalate and 2- isopropylmalate. Here the step C, i.e., the conversion of 3-isopropylmalate into α-ketoisocaproate, does not occur due to mutation, which prevents the further synthesis of leucine.

Leu-2 contains a mutant protein that is unable to synthesize the 3-isopropylmalate. This is because this strain is unable to grow on the minimal media, supplied with 2-isopropylmalate. The mutation in enzyme involved in step B that prevents the synthesis of 3-isopropylmalate from 2-isopropylmalate, thus, the final product leucine.

Conclusion

Thus, it can be concluded from the given data that the Leu-1 strain has a mutant protein that prevents the catalysis of step C and Leu-2 strain has a mutant protein that is unable to catalyze the step B of the given biosynthetic pathway.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Older adults have unique challenges in terms of their nutrient needs and physiological changes. Some changes may make it difficult to consume a healthful diet, so it is important to identify strategies to help overcome these obstacles. From the list below, choose all the correct statements about changes in older adults. Select all that apply. Poor vision can make it difficult for older adults to get to a supermarket, and to prepare meals. With age, taste and visual perception decline. As people age, salivary production increases. In older adults with dysphagia, foods like creamy soups, applesauce, and yogurt are usually well tolerated. Lean body mass increases in older adults.

When physical activity increases, energy requirements increase also. Depending on the type, intensity, and duration of physical activity, the body’s requirements for certain macronutrients may change as well. From the list below, choose all the correct statements about the effects of increased physical activity or athletic training. Select all that apply. An athlete who weighs 70 kg (154 lb) should consume 420 to 700 g of carbohydrate per day. How much additional energy an athlete needs depends on the specific activity the athlete engages in and the frequency of the activity. Those participating in vigorous exercise should restrict their fat intake to less than 15%% of total energy intake. Athletes who are following energy-restricted diets are at risk for consuming insufficient protein. The recommendation to limit saturated fat intake to less than 10%% of total energy intake does not apply to athletes or those who regularly engage in vigorous physical activity.

When taking vitamins and vitamin-mineral supplements, how can one be sure they are getting what they are taking?

Answer 2

Question

Chapter 14, Problem 1Q

Summary Introduction

To analyze:

The steps of the biosynthetic pathway that are associated with each type of mutation from the given data.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild-type (haploid) + + + + +

Leu-1 (haploid) − − + − +

Leu-2 (haploid) − − + + +

Fused cells (diploid): Leu-1, Leu-2 − + + + +

The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Expert Solution & Answer

Explanation of Solution

Neurospora is able to synthesize leucine in their cells and hence, are able to grow on a minimal medium (a medium that does not contain additional amino acids). The mutant strains of Neurospora lack the precursors that are required to perform the metabolic steps for the leucine synthesis. The two important mutant strains of Neurospora are Leu-1 and Leu-2.

From the given table and diagram, it is observed that Leu-1 strain contains a mutation in the protein that is required for the synthesis of α-ketoisocaproate. This is because this strain is unable to grow in the minimal medium supplied with 3-isopropylmalate and 2- isopropylmalate. Here the step C, i.e., the conversion of 3-isopropylmalate into α-ketoisocaproate, does not occur due to mutation, which prevents the further synthesis of leucine.

Leu-2 contains a mutant protein that is unable to synthesize the 3-isopropylmalate. This is because this strain is unable to grow on the minimal media, supplied with 2-isopropylmalate. The mutation in enzyme involved in step B that prevents the synthesis of 3-isopropylmalate from 2-isopropylmalate, thus, the final product leucine.

Conclusion

Thus, it can be concluded from the given data that the Leu-1 strain has a mutant protein that prevents the catalysis of step C and Leu-2 strain has a mutant protein that is unable to catalyze the step B of the given biosynthetic pathway.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 14, Problem 1Q

Summary Introduction

To analyze:

The steps of the biosynthetic pathway that are associated with each type of mutation from the given data.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild-type (haploid) + + + + +

Leu-1 (haploid) − − + − +

Leu-2 (haploid) − − + + +

Fused cells (diploid): Leu-1, Leu-2 − + + + +

The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Expert Solution & Answer

Explanation of Solution

Neurospora is able to synthesize leucine in their cells and hence, are able to grow on a minimal medium (a medium that does not contain additional amino acids). The mutant strains of Neurospora lack the precursors that are required to perform the metabolic steps for the leucine synthesis. The two important mutant strains of Neurospora are Leu-1 and Leu-2.

From the given table and diagram, it is observed that Leu-1 strain contains a mutation in the protein that is required for the synthesis of α-ketoisocaproate. This is because this strain is unable to grow in the minimal medium supplied with 3-isopropylmalate and 2- isopropylmalate. Here the step C, i.e., the conversion of 3-isopropylmalate into α-ketoisocaproate, does not occur due to mutation, which prevents the further synthesis of leucine.

Leu-2 contains a mutant protein that is unable to synthesize the 3-isopropylmalate. This is because this strain is unable to grow on the minimal media, supplied with 2-isopropylmalate. The mutation in enzyme involved in step B that prevents the synthesis of 3-isopropylmalate from 2-isopropylmalate, thus, the final product leucine.

Conclusion

Thus, it can be concluded from the given data that the Leu-1 strain has a mutant protein that prevents the catalysis of step C and Leu-2 strain has a mutant protein that is unable to catalyze the step B of the given biosynthetic pathway.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 14, Problem 1Q

Summary Introduction

To analyze:

The steps of the biosynthetic pathway that are associated with each type of mutation from the given data.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild-type (haploid) + + + + +

Leu-1 (haploid) − − + − +

Leu-2 (haploid) − − + + +

Fused cells (diploid): Leu-1, Leu-2 − + + + +

The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Expert Solution & Answer

Explanation of Solution

Neurospora is able to synthesize leucine in their cells and hence, are able to grow on a minimal medium (a medium that does not contain additional amino acids). The mutant strains of Neurospora lack the precursors that are required to perform the metabolic steps for the leucine synthesis. The two important mutant strains of Neurospora are Leu-1 and Leu-2.

From the given table and diagram, it is observed that Leu-1 strain contains a mutation in the protein that is required for the synthesis of α-ketoisocaproate. This is because this strain is unable to grow in the minimal medium supplied with 3-isopropylmalate and 2- isopropylmalate. Here the step C, i.e., the conversion of 3-isopropylmalate into α-ketoisocaproate, does not occur due to mutation, which prevents the further synthesis of leucine.

Leu-2 contains a mutant protein that is unable to synthesize the 3-isopropylmalate. This is because this strain is unable to grow on the minimal media, supplied with 2-isopropylmalate. The mutation in enzyme involved in step B that prevents the synthesis of 3-isopropylmalate from 2-isopropylmalate, thus, the final product leucine.

Conclusion

Thus, it can be concluded from the given data that the Leu-1 strain has a mutant protein that prevents the catalysis of step C and Leu-2 strain has a mutant protein that is unable to catalyze the step B of the given biosynthetic pathway.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 14, Problem 1Q

Summary Introduction

To analyze:

The steps of the biosynthetic pathway that are associated with each type of mutation from the given data.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild-type (haploid) + + + + +

Leu-1 (haploid) − − + − +

Leu-2 (haploid) − − + + +

Fused cells (diploid): Leu-1, Leu-2 − + + + +

The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Expert Solution & Answer

Explanation of Solution

Neurospora is able to synthesize leucine in their cells and hence, are able to grow on a minimal medium (a medium that does not contain additional amino acids). The mutant strains of Neurospora lack the precursors that are required to perform the metabolic steps for the leucine synthesis. The two important mutant strains of Neurospora are Leu-1 and Leu-2.

From the given table and diagram, it is observed that Leu-1 strain contains a mutation in the protein that is required for the synthesis of α-ketoisocaproate. This is because this strain is unable to grow in the minimal medium supplied with 3-isopropylmalate and 2- isopropylmalate. Here the step C, i.e., the conversion of 3-isopropylmalate into α-ketoisocaproate, does not occur due to mutation, which prevents the further synthesis of leucine.

Leu-2 contains a mutant protein that is unable to synthesize the 3-isopropylmalate. This is because this strain is unable to grow on the minimal media, supplied with 2-isopropylmalate. The mutation in enzyme involved in step B that prevents the synthesis of 3-isopropylmalate from 2-isopropylmalate, thus, the final product leucine.

Conclusion

Thus, it can be concluded from the given data that the Leu-1 strain has a mutant protein that prevents the catalysis of step C and Leu-2 strain has a mutant protein that is unable to catalyze the step B of the given biosynthetic pathway.

Answer 6

Chapter 14, Problem 1Q

Summary Introduction

To analyze:

The steps of the biosynthetic pathway that are associated with each type of mutation from the given data.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild-type (haploid) + + + + +

Leu-1 (haploid) − − + − +

Leu-2 (haploid) − − + + +

Fused cells (diploid): Leu-1, Leu-2 − + + + +

The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Expert Solution & Answer

Explanation of Solution

Neurospora is able to synthesize leucine in their cells and hence, are able to grow on a minimal medium (a medium that does not contain additional amino acids). The mutant strains of Neurospora lack the precursors that are required to perform the metabolic steps for the leucine synthesis. The two important mutant strains of Neurospora are Leu-1 and Leu-2.

From the given table and diagram, it is observed that Leu-1 strain contains a mutation in the protein that is required for the synthesis of α-ketoisocaproate. This is because this strain is unable to grow in the minimal medium supplied with 3-isopropylmalate and 2- isopropylmalate. Here the step C, i.e., the conversion of 3-isopropylmalate into α-ketoisocaproate, does not occur due to mutation, which prevents the further synthesis of leucine.

Leu-2 contains a mutant protein that is unable to synthesize the 3-isopropylmalate. This is because this strain is unable to grow on the minimal media, supplied with 2-isopropylmalate. The mutation in enzyme involved in step B that prevents the synthesis of 3-isopropylmalate from 2-isopropylmalate, thus, the final product leucine.

Conclusion

Thus, it can be concluded from the given data that the Leu-1 strain has a mutant protein that prevents the catalysis of step C and Leu-2 strain has a mutant protein that is unable to catalyze the step B of the given biosynthetic pathway.

Answer 7

Chapter 14, Problem 1Q

Summary Introduction

To analyze:

The steps of the biosynthetic pathway that are associated with each type of mutation from the given data.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused-type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild-type (haploid) + + + + +

Leu-1 (haploid) − − + − +

Leu-2 (haploid) − − + + +

Fused cells (diploid): Leu-1, Leu-2 − + + + +

The following reaction shows the steps involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

The leucine is an essential amino acid that is basic in nature because of the presence of an amino group. Some organisms like Neurospora are able to catalyze the synthesis of leucine in their cells. The Neurospora is a haploid fungus that is used as a model organism because it is able to grow quickly on the minimal media in the laboratory.

Answer 8

Expert Solution & Answer

Explanation of Solution

Neurospora is able to synthesize leucine in their cells and hence, are able to grow on a minimal medium (a medium that does not contain additional amino acids). The mutant strains of Neurospora lack the precursors that are required to perform the metabolic steps for the leucine synthesis. The two important mutant strains of Neurospora are Leu-1 and Leu-2.

From the given table and diagram, it is observed that Leu-1 strain contains a mutation in the protein that is required for the synthesis of α-ketoisocaproate. This is because this strain is unable to grow in the minimal medium supplied with 3-isopropylmalate and 2- isopropylmalate. Here the step C, i.e., the conversion of 3-isopropylmalate into α-ketoisocaproate, does not occur due to mutation, which prevents the further synthesis of leucine.

Leu-2 contains a mutant protein that is unable to synthesize the 3-isopropylmalate. This is because this strain is unable to grow on the minimal media, supplied with 2-isopropylmalate. The mutation in enzyme involved in step B that prevents the synthesis of 3-isopropylmalate from 2-isopropylmalate, thus, the final product leucine.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Conclusion

Thus, it can be concluded from the given data that the Leu-1 strain has a mutant protein that prevents the catalysis of step C and Leu-2 strain has a mutant protein that is unable to catalyze the step B of the given biosynthetic pathway.

Answer 12

Ch. 14.1 - Prob. 1R Ch. 14.1 - Prob. 2R Ch. 14.1 - Prob. 3R Ch. 14.2 - Prob. 1R Ch. 14.2 - Prob. 2R Ch. 14.3 - Prob. 1R Ch. 14.3 - Prob. 2R Ch. 14.3 - Prob. 3R Ch. 14.4 - Prob. 1R Ch. 14.4 - Prob. 2R

Concept explainers

Videos

Explanation of Solution

Want to see more full solutions like this?

Chapter 14 Solutions

Types of strains used in the experiment	The growth of different strains of Neurospora in different media
Types of strains used in the experiment	Minimal medium	Minimal medium+2-isopropylmalate	Minimal medium+leucine	Minimal medium+3-isopropylmalate	Minimal medium+α-ketoisocaproate
Wild-type (haploid)	+	+	+	+	+
Leu-1 (haploid)	−	−	+	−	+
Leu-2 (haploid)	−	−	+	+	+
Fused cells (diploid): Leu-1, Leu-2	−	+	+	+	+