The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains. Given: Two mutant strains of Neurospora ( Leu- 1 and Leu- 2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−). Table 1: The results of the growth of different strains of Neurospora in different media. Types of strains used in the experiment The growth of different strains of Neurospora in different media Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate Wild type (haploid) + + + + + Leu- 1 (haploid) - - + - + Leu -2 (haploid) - - + + + Fused cells (diploid): Leu -1, Leu -2 - + + + + The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1). Figure 1: Introduction: Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow. However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Question

Want to see the full answer?

Answer 1

Question

Chapter 14, Problem 3Q

Summary Introduction

To review:

The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild type (haploid) + + + + +

Leu-1 (haploid) - - + - +

Leu-2 (haploid) - - + + +

Fused cells (diploid): Leu-1, Leu-2 - + + + +

The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow.

However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Based on your results from the Mannitol Salt Agar (MSA) media, which of your bacteria were mannitol fermenters and which were not mannitol fermenters?

help tutor please

Q8. A researcher wants to study the effectiveness of a pill intended to reduce stomach heartburn in pregnant women. The researcher chooses randomly 400 women to participate in this experiment for 9 months of their pregnancy period. They all need to have the same diet. The researcher designs two groups of 200 participants: One group take the real medication intended to reduce heartburn, while the other group take placebo medication. In this study what are: Independent variable: Dependent variable: Control variable: Experimental group: " Control group: If the participants do not know who is consuming the real pills and who is consuming the sugar pills. This study is It happens that 40% of the participants do not find the treatment helpful and drop out after 6 months. The researcher throws out the data from subjects that drop out. What type of bias is there in this study? If the company who makes the medication funds this research, what type of bias might exist in this research work?

Answer 2

Question

Chapter 14, Problem 3Q

Summary Introduction

To review:

The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild type (haploid) + + + + +

Leu-1 (haploid) - - + - +

Leu-2 (haploid) - - + + +

Fused cells (diploid): Leu-1, Leu-2 - + + + +

The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow.

However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 14, Problem 3Q

Summary Introduction

To review:

The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild type (haploid) + + + + +

Leu-1 (haploid) - - + - +

Leu-2 (haploid) - - + + +

Fused cells (diploid): Leu-1, Leu-2 - + + + +

The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow.

However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 14, Problem 3Q

Summary Introduction

To review:

The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild type (haploid) + + + + +

Leu-1 (haploid) - - + - +

Leu-2 (haploid) - - + + +

Fused cells (diploid): Leu-1, Leu-2 - + + + +

The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow.

However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 14, Problem 3Q

Summary Introduction

To review:

The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild type (haploid) + + + + +

Leu-1 (haploid) - - + - +

Leu-2 (haploid) - - + + +

Fused cells (diploid): Leu-1, Leu-2 - + + + +

The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow.

However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Answer 6

Chapter 14, Problem 3Q

Summary Introduction

To review:

The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild type (haploid) + + + + +

Leu-1 (haploid) - - + - +

Leu-2 (haploid) - - + + +

Fused cells (diploid): Leu-1, Leu-2 - + + + +

The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow.

However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Answer 7

Chapter 14, Problem 3Q

Summary Introduction

To review:

The information that would be gathered after measuring the activities of the enzymes that catalyze the steps A, B, C, and D in the fused diploid and each haploid mutant strains.

Given:

Two mutant strains of Neurospora (Leu-1 and Leu-2), the wild-type and the fused type were supplied with different nutrient media and their growth was recorded in Table 1. The presence of growth is indicated by the positive sign (+) and the absence of growth is indicated by the negative sign (−).

Table 1: The results of the growth of different strains of Neurospora in different media.

Types of strains used in the experiment The growth of different strains of Neurospora in different media

Minimal medium Minimal medium+2-isopropylmalate Minimal medium+leucine Minimal medium+3-isopropylmalate Minimal medium+α-ketoisocaproate

Wild type (haploid) + + + + +

Leu-1 (haploid) - - + - +

Leu-2 (haploid) - - + + +

Fused cells (diploid): Leu-1, Leu-2 - + + + +

The following metabolic reaction represents the steps, which are involved in the synthesis of leucine in Neurospora (Figure 1).

Figure 1:

Introduction:

Neurospora is a haploid organism and is able to grow in the minimal medium. The minimal medium is the medium that contains only the simple components that are required for the organism’s survival and lacks any additional amino acids. Neurospora is able to synthesize the amino acid leucine and hence, does not require the same in its medium, in order to grow.

However, the mutant strains lack one of the enzymes that are required in the leucine synthesis and therefore, are unable to grow on the minimal medium. Different types of media are used to differentiate between the wild-type and the mutant strains of the Neurospora.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 14.1 - Prob. 1R Ch. 14.1 - Prob. 2R Ch. 14.1 - Prob. 3R Ch. 14.2 - Prob. 1R Ch. 14.2 - Prob. 2R Ch. 14.3 - Prob. 1R Ch. 14.3 - Prob. 2R Ch. 14.3 - Prob. 3R Ch. 14.4 - Prob. 1R Ch. 14.4 - Prob. 2R

Solution Summary: The author explains that the haploid mutants of Neurospora lack one of the enzymes that are required to synthesise lysine.

Videos

Want to see the full answer?

Chapter 14 Solutions

Types of strains used in the experiment	The growth of different strains of Neurospora in different media
Types of strains used in the experiment		Minimal medium	Minimal medium+2-isopropylmalate	Minimal medium+leucine	Minimal medium+3-isopropylmalate	Minimal medium+α-ketoisocaproate
Wild type (haploid)	+	+	+	+	+
Leu-1 (haploid)	-	-	+	-	+
Leu-2 (haploid)	-	-	+	+	+
Fused cells (diploid): Leu-1, Leu-2	-	+	+	+	+