Chapter 14, Problem 14.68EP

(a)

Interpretation Introduction

Interpretation:

The structure of alcohol that could be used to prepare the given compound by oxidation reaction has to be drawn.

Concept Introduction:

In organic chemistry, oxidation reaction is referred to the number $\text{C}-\text{O}$ bonds increase and/or number of $\text{C}-\text{H}$ bonds decrease.

In organic chemistry, reduction reaction is referred to the number $\text{C}-\text{O}$ bonds decrease and/or number of $\text{C}-\text{H}$ bonds increase.

Alcohols do undergo oxidation reaction and reduction reaction.  This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom.  Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction.  Primary alcohols undergo oxidation to give aldehyde and this id further oxidized to give carboxylic acid as product.  Secondary alcohol undergoes oxidation to give ketone as the product.

Primary alcohol:

Secondary alcohol:

Answer to Problem 14.68EP

The structure of alcohol is,

Explanation of Solution

In organic chemistry, oxidation reaction is said to be decrease in $\text{C}-\text{H}$ bonds or increase in $\text{C}-\text{O}$ bonds.  The structure of given product is,

The given compound is a aldehyde.  The aldehyde must have formed from primary alcohol by oxidation.  The structure of the primary alcohol can be drawn considering the general scheme.  Therefore, the structure can be given as shown below,

Conclusion

Structure of alcohol is drawn from which the given product is obtained by oxidation.

(b)

Interpretation Introduction

Interpretation:

The structure of alcohol that could be used to prepare the given compound by oxidation reaction has to be drawn.

Concept Introduction:

In organic chemistry, oxidation reaction is referred to the number $\text{C}-\text{O}$ bonds increase and/or number of $\text{C}-\text{H}$ bonds decrease.

In organic chemistry, reduction reaction is referred to the number $\text{C}-\text{O}$ bonds decrease and/or number of $\text{C}-\text{H}$ bonds increase.

Alcohols do undergo oxidation reaction and reduction reaction.  This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom.  Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction.  Primary alcohols undergo oxidation to give aldehyde and this id further oxidized to give carboxylic acid as product.  Secondary alcohol undergoes oxidation to give ketone as the product.

Primary alcohol:

Secondary alcohol:

Answer to Problem 14.68EP

The structure of alcohol is,

Explanation of Solution

In organic chemistry, oxidation reaction is said to be decrease in $\text{C}-\text{H}$ bonds or increase in $\text{C}-\text{O}$ bonds.  The structure of given product is,

The given compound is a ketone.  This has to be formed from a secondary alcohol only on oxidation.  The structure of the secondary alcohol can be drawn considering the general scheme.  Therefore, the structure can be given as shown below,

Conclusion

Structure of alcohol is drawn from which the given product is obtained by oxidation.

(c)

Interpretation Introduction

Interpretation:

The structure of alcohol that could be used to prepare the given compound by oxidation reaction has to be drawn.

Concept Introduction:

In organic chemistry, oxidation reaction is referred to the number $\text{C}-\text{O}$ bonds increase and/or number of $\text{C}-\text{H}$ bonds decrease.

In organic chemistry, reduction reaction is referred to the number $\text{C}-\text{O}$ bonds decrease and/or number of $\text{C}-\text{H}$ bonds increase.

Alcohols do undergo oxidation reaction and reduction reaction.  This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom.  Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction.  Primary alcohols undergo oxidation to give aldehyde and this id further oxidized to give carboxylic acid as product.  Secondary alcohol undergoes oxidation to give ketone as the product.

Primary alcohol:

Secondary alcohol:

Answer to Problem 14.68EP

The structure of alcohol is,

Explanation of Solution

In organic chemistry, oxidation reaction is said to be decrease in $\text{C}-\text{H}$ bonds or increase in $\text{C}-\text{O}$ bonds.  The structure of given product is,

The given compound is a carboxylic acid.  This has to be formed from aldehyde by oxidation.  The aldehyde must have formed from primary alcohol by oxidation.  The structure of the primary alcohol can be drawn considering the general scheme.  Therefore, the structure can be given as shown below,

Conclusion

Structure of alcohol is drawn from which the given product is obtained by oxidation.

(d)

Interpretation Introduction

Interpretation:

The structure of alcohol that could be used to prepare the given compound by oxidation reaction has to be drawn.

Concept Introduction:

In organic chemistry, oxidation reaction is referred to the number $\text{C}-\text{O}$ bonds increase and/or number of $\text{C}-\text{H}$ bonds decrease.

In organic chemistry, reduction reaction is referred to the number $\text{C}-\text{O}$ bonds decrease and/or number of $\text{C}-\text{H}$ bonds increase.

Alcohols do undergo oxidation reaction and reduction reaction.  This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom.  Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction.  Primary alcohols undergo oxidation to give aldehyde and this id further oxidized to give carboxylic acid as product.  Secondary alcohol undergoes oxidation to give ketone as the product.

Primary alcohol:

Secondary alcohol:

Answer to Problem 14.68EP

The structure of alcohol is,

Explanation of Solution

In organic chemistry, oxidation reaction is said to be decrease in $\text{C}-\text{H}$ bonds or increase in $\text{C}-\text{O}$ bonds.  The structure of given product is,

The given compound is a aldehyde.  The aldehyde must have formed from primary alcohol by oxidation.  The structure of the primary alcohol can be drawn considering the general scheme.  Therefore, the structure can be given as shown below,

Conclusion

Structure of alcohol is drawn from which the given product is obtained by oxidation.