General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
7th Edition
ISBN: 9781305253070
Author: STOKER, H. Stephen
Publisher: Cengage Learning
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Chapter 14, Problem 14.1EP

(a)

Interpretation Introduction

Interpretation:

The number of covalent bonds that oxygen atom can form in an organic compound has to be given.

Concept Introduction:

All the atoms try to attain the octet configuration. They either gain or lose electrons, or share the electrons to get the stable octet structure. Covalent bonds are formed by mutual sharing of electrons between the atoms.

(a)

Expert Solution
Check Mark

Answer to Problem 14.1EP

Oxygen can form two covalent bonds.

Explanation of Solution

Oxygen is a Group VIA element. Therefore, it has six valence electrons. All the elements try to attain the stable octet configuration either by losing, gaining or sharing the valence electrons. Oxygen is short of two electrons in order to obtain the octet configuration. Therefore, oxygen forms two bonds.

Conclusion

Oxygen is found to form two covalent bonds in organic compounds.

(b)

Interpretation Introduction

Interpretation:

The number of covalent bonds that Hydrogen atom can form in an organic compound has to be given.

Concept Introduction:

All the atoms try to attain the octet configuration. They either gain or lose electrons, or share the electrons to get the stable octet structure. Covalent bonds are formed by mutual sharing of electrons between the atoms.

(b)

Expert Solution
Check Mark

Answer to Problem 14.1EP

Hydrogen can form one covalent bond.

Explanation of Solution

Hydrogen is a Group IA element. Therefore, it has only one valence electron. All the elements try to attain the stable octet configuration either by losing, gaining or sharing the valence electrons. Hydrogen is short of one electron in order to obtain the complete shell configuration. Therefore, hydrogen forms one covalent bond.

Conclusion

Hydrogen is found to form one covalent bond in organic compounds.

(c)

Interpretation Introduction

Interpretation:

The number of covalent bonds that carbon atom can form in an organic compound has to be given.

Concept Introduction:

All the atoms try to attain the octet configuration. They either gain or lose electrons, or share the electrons to get the stable octet structure. Covalent bonds are formed by mutual sharing of electrons between the atoms.

(c)

Expert Solution
Check Mark

Answer to Problem 14.1EP

Carbon can form four covalent bonds.

Explanation of Solution

Carbon is a Group IVA element. Therefore, it has four valence electrons. All the elements try to attain the stable octet configuration either by losing, gaining or sharing the valence electrons. Carbon is short of four electrons in order to obtain the octet configuration. Therefore, carbon forms four covalent bonds.

Conclusion

Carbon is found to form four covalent bonds in organic compounds.

(d)

Interpretation Introduction

Interpretation:

The number of covalent bonds that halogen atom can form in an organic compound has to be given.

Concept Introduction:

All the atoms try to attain the octet configuration. They either gain or lose electrons, or share the electrons to get the stable octet structure. Covalent bonds are formed by mutual sharing of electrons between the atoms.

(d)

Expert Solution
Check Mark

Answer to Problem 14.1EP

Halogen can form one covalent bond.

Explanation of Solution

Halogens are present in Group VIIA of periodic table. Therefore, it has seven valence electrons. All the elements try to attain the stable octet configuration either by losing, gaining or sharing the valence electrons. Halogens are in short of one electron in order to obtain the octet configuration. Therefore, halogens form one covalent bond.

Conclusion

Halogens are found to form one covalent bond in organic compounds.

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Chapter 14 Solutions

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)

Ch. 14.4 - Prob. 2QQCh. 14.4 - Prob. 3QQCh. 14.5 - Prob. 1QQCh. 14.5 - Prob. 2QQCh. 14.5 - Prob. 3QQCh. 14.5 - Prob. 4QQCh. 14.6 - Prob. 1QQCh. 14.6 - Prob. 2QQCh. 14.6 - Prob. 3QQCh. 14.7 - Prob. 1QQCh. 14.7 - Prob. 2QQCh. 14.8 - Prob. 1QQCh. 14.8 - Prob. 2QQCh. 14.9 - Prob. 1QQCh. 14.9 - Prob. 2QQCh. 14.9 - Prob. 3QQCh. 14.9 - Prob. 4QQCh. 14.9 - Prob. 5QQCh. 14.9 - Prob. 6QQCh. 14.10 - Prob. 1QQCh. 14.10 - Prob. 2QQCh. 14.11 - Prob. 1QQCh. 14.11 - Prob. 2QQCh. 14.11 - Prob. 3QQCh. 14.12 - Prob. 1QQCh. 14.12 - Prob. 2QQCh. 14.13 - Prob. 1QQCh. 14.13 - Prob. 2QQCh. 14.13 - Prob. 3QQCh. 14.14 - Prob. 1QQCh. 14.14 - Prob. 2QQCh. 14.14 - Prob. 3QQCh. 14.15 - Prob. 1QQCh. 14.15 - Prob. 2QQCh. 14.15 - Prob. 3QQCh. 14.15 - Prob. 4QQCh. 14.16 - Prob. 1QQCh. 14.16 - Prob. 2QQCh. 14.17 - Prob. 1QQCh. 14.17 - Prob. 2QQCh. 14.17 - Prob. 3QQCh. 14.18 - Prob. 1QQCh. 14.18 - Prob. 2QQCh. 14.18 - Prob. 3QQCh. 14.19 - Prob. 1QQCh. 14.19 - Prob. 2QQCh. 14.20 - Prob. 1QQCh. 14.20 - Prob. 2QQCh. 14.20 - Prob. 3QQCh. 14.20 - Prob. 4QQCh. 14.20 - Prob. 5QQCh. 14.21 - Prob. 1QQCh. 14.21 - Prob. 2QQCh. 14.21 - Prob. 3QQCh. 14.21 - Prob. 4QQCh. 14.21 - Prob. 5QQCh. 14 - Prob. 14.1EPCh. 14 - Prob. 14.2EPCh. 14 - Prob. 14.3EPCh. 14 - Prob. 14.4EPCh. 14 - Prob. 14.5EPCh. 14 - Prob. 14.6EPCh. 14 - Prob. 14.7EPCh. 14 - Prob. 14.8EPCh. 14 - Prob. 14.9EPCh. 14 - Prob. 14.10EPCh. 14 - Write a condensed structural formula for each of...Ch. 14 - Write a condensed structural formula for each of...Ch. 14 - Prob. 14.13EPCh. 14 - Prob. 14.14EPCh. 14 - Prob. 14.15EPCh. 14 - Prob. 14.16EPCh. 14 - Prob. 14.17EPCh. 14 - Prob. 14.18EPCh. 14 - Each of the following alcohols is named...Ch. 14 - Prob. 14.20EPCh. 14 - Prob. 14.21EPCh. 14 - Prob. 14.22EPCh. 14 - Prob. 14.23EPCh. 14 - Prob. 14.24EPCh. 14 - Prob. 14.25EPCh. 14 - Prob. 14.26EPCh. 14 - Prob. 14.27EPCh. 14 - Prob. 14.28EPCh. 14 - Prob. 14.29EPCh. 14 - Prob. 14.30EPCh. 14 - Prob. 14.31EPCh. 14 - Prob. 14.32EPCh. 14 - Prob. 14.33EPCh. 14 - Prob. 14.34EPCh. 14 - Explain why the boiling points of alcohols are...Ch. 14 - Explain why the water solubilities of alcohols are...Ch. 14 - Prob. 14.37EPCh. 14 - Prob. 14.38EPCh. 14 - Prob. 14.39EPCh. 14 - Which member of each of the following pairs of...Ch. 14 - Determine the maximum number of hydrogen bonds...Ch. 14 - Determine the maximum number of hydrogen bonds...Ch. 14 - Prob. 14.43EPCh. 14 - Prob. 14.44EPCh. 14 - Prob. 14.45EPCh. 14 - Prob. 14.46EPCh. 14 - Classify each of the following alcohols as a...Ch. 14 - Classify each of the following alcohols as a...Ch. 14 - Classify each of the following alcohols as a...Ch. 14 - Classify each of the following alcohols as a...Ch. 14 - Prob. 14.51EPCh. 14 - Prob. 14.52EPCh. 14 - Prob. 14.53EPCh. 14 - Prob. 14.54EPCh. 14 - Prob. 14.55EPCh. 14 - Prob. 14.56EPCh. 14 - Prob. 14.57EPCh. 14 - Prob. 14.58EPCh. 14 - Prob. 14.59EPCh. 14 - Prob. 14.60EPCh. 14 - The alcohol 2,2-dimethyl-1-butanol cannot be...Ch. 14 - Prob. 14.62EPCh. 14 - Prob. 14.63EPCh. 14 - Prob. 14.64EPCh. 14 - Draw the structure of the aldehyde or ketone...Ch. 14 - Draw the structure of the aldehyde or ketone...Ch. 14 - Prob. 14.67EPCh. 14 - Prob. 14.68EPCh. 14 - Prob. 14.69EPCh. 14 - Prob. 14.70EPCh. 14 - Three isomeric pentanols with unbranched carbon...Ch. 14 - Prob. 14.72EPCh. 14 - Prob. 14.73EPCh. 14 - Prob. 14.74EPCh. 14 - Prob. 14.75EPCh. 14 - Prob. 14.76EPCh. 14 - Prob. 14.77EPCh. 14 - Prob. 14.78EPCh. 14 - Prob. 14.79EPCh. 14 - Prob. 14.80EPCh. 14 - Prob. 14.81EPCh. 14 - Prob. 14.82EPCh. 14 - Prob. 14.83EPCh. 14 - Prob. 14.84EPCh. 14 - Prob. 14.85EPCh. 14 - Prob. 14.86EPCh. 14 - Prob. 14.87EPCh. 14 - Prob. 14.88EPCh. 14 - Prob. 14.89EPCh. 14 - Prob. 14.90EPCh. 14 - Prob. 14.91EPCh. 14 - Classify each of the following compounds as an...Ch. 14 - Draw or write the following for the simplest ether...Ch. 14 - Draw or write the following for the simplest ether...Ch. 14 - Prob. 14.95EPCh. 14 - Prob. 14.96EPCh. 14 - Prob. 14.97EPCh. 14 - Prob. 14.98EPCh. 14 - Prob. 14.99EPCh. 14 - Prob. 14.100EPCh. 14 - Prob. 14.101EPCh. 14 - Prob. 14.102EPCh. 14 - Prob. 14.103EPCh. 14 - Prob. 14.104EPCh. 14 - Prob. 14.105EPCh. 14 - Prob. 14.106EPCh. 14 - Prob. 14.107EPCh. 14 - Prob. 14.108EPCh. 14 - Prob. 14.109EPCh. 14 - Prob. 14.110EPCh. 14 - Prob. 14.111EPCh. 14 - Prob. 14.112EPCh. 14 - Prob. 14.113EPCh. 14 - Give common names for all ethers that are...Ch. 14 - How many isomeric ethers exist when the R groups...Ch. 14 - Prob. 14.116EPCh. 14 - Prob. 14.117EPCh. 14 - Draw condensed structural formulas for the...Ch. 14 - Prob. 14.119EPCh. 14 - Prob. 14.120EPCh. 14 - Prob. 14.121EPCh. 14 - Prob. 14.122EPCh. 14 - Prob. 14.123EPCh. 14 - How do the chemical reactivities of ethers compare...Ch. 14 - Explain why ether molecules cannot hydrogen-bond...Ch. 14 - How many hydrogen bonds can form between a single...Ch. 14 - Classify each of the following molecular...Ch. 14 - Classify each of the following molecular...Ch. 14 - Prob. 14.129EPCh. 14 - Prob. 14.130EPCh. 14 - Prob. 14.131EPCh. 14 - Draw a condensed structural formula for each of...Ch. 14 - Prob. 14.133EPCh. 14 - Prob. 14.134EPCh. 14 - Prob. 14.135EPCh. 14 - Prob. 14.136EPCh. 14 - Prob. 14.137EPCh. 14 - For each of the following pairs of compounds,...Ch. 14 - Assign an IUPAC name to each of the following...Ch. 14 - Prob. 14.140EPCh. 14 - Prob. 14.141EPCh. 14 - Prob. 14.142EPCh. 14 - Prob. 14.143EPCh. 14 - Prob. 14.144EPCh. 14 - Prob. 14.145EPCh. 14 - Prob. 14.146EP
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