Explanation The equation representing the autoionization of water is given below. 2 H 2 O ( l ) ⇌ H 3 O + ( a q ) + O H − ( a q ) The equilibrium constant for the above equation can be written as given below. K w = [ H 3 O + ] [ O H − ] According to the question. Only the first ionization is important to determine the p H . A table can be set up as given below. H 3 O + ( a q ) O H − ( a q ) I n i t i a l c o n c . ( M ) 0 0 C h a n g e i n c o n c . ( M ) + x + x E q u i l i b r i u m c o n c . ( M ) x x So, at equilibrium, K w = x 2 The ionization constant for water at various temperatures are given below. Figure 1 At 10 ∘ C : x = 0.29 × 10 − 14 = 5.4 × 10 − 8 M = [ H 3 O + ] p H = − log [ H 3 O + ] = − log ( 5.4 × 10 − 8 ) = 7

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

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ISBN: 9781285460420

Author: John W. Moore; Conrad L. Stanitski

Publisher: Cengage Learning US

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Chapter 14, Problem 106QRT

Interpretation Introduction

Interpretation:

The pH of pure water at 10∘C, 25∘C and 50∘C has to be calculated. The classification of the water at each temperature as either acidic, neutral, or basic has to be done.

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Chapter 14, Problem 105QRT

Chapter 14, Problem 107QRT

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Chapter 14 Solutions

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

Ch. 14.1 - Identify each molecule or ion as a Brnsted-Lowry...Ch. 14.1 - Using Le Chatelier’s Principle Use Le Chatelier’s...Ch. 14.1 - Prob. 14.3E Ch. 14.1 - Complete the table. Ch. 14.1 - Prob. 14.4E Ch. 14.1 - Prob. 14.5E Ch. 14.2 - Prob. 14.6CE Ch. 14.2 - Prob. 14.7E Ch. 14.3 - Prob. 14.2PSP Ch. 14.3 - Prob. 14.3PSP

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The p H of pure water at 10 ∘ C , 25 ∘ C a n d 50 ∘ C has to be calculated. The classification of the water at each temperature as either acidic, neutral, or basic has to be done.

Solution Summary: The author explains that the pH of pure water at different temperatures has to be calculated. The equation representing the autoionization of water is given below.

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Interpretation:

The pH of pure water at 10∘C, 25∘C and 50∘C has to be calculated. The classification of the water at each temperature as either acidic, neutral, or basic has to be done.

Want to see the full answer?

Chapter 14 Solutions

The p H of pure water at 10 ∘ C , 25 ∘ C a n d 50 ∘ C has to be calculated. The classification of the water at each temperature as either acidic, neutral, or basic has to be done.

Solution Summary: The author explains that the pH of pure water at different temperatures has to be calculated. The equation representing the autoionization of water is given below.

Concept explainers

Videos

Interpretation: The pH of pure water at 10∘C, 25∘C and 50∘C has to be calculated. The classification of the water at each temperature as either acidic, neutral, or basic has to be done.

Want to see the full answer?

Chapter 14 Solutions

Interpretation:

The pH of pure water at 10∘C, 25∘C and 50∘C has to be calculated. The classification of the water at each temperature as either acidic, neutral, or basic has to be done.