Explanation The current p H of ocean’s surface water is 8.1. So the concentration of H 3 O + can be calculated from this p H . [ H 3 O + ] n o w = 10 − p H = 10 − 8.1 = 8 × 10 − 9 M . According to question the concentration of H 3 O + is 30 % increase from the mid- 1800 s . Hence, it can be written as follows, ( 130 % ) [ H 3 O + ] 1800 s = 100 % [ H 3 O + ]

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

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ISBN: 9781285460420

Author: John W. Moore; Conrad L. Stanitski

Publisher: Cengage Learning US

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Chapter 14, Problem 102QRT

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The pH of ocean’s surface water in the mid-1800s has to be calculated.

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Chapter 14, Problem 101QRT

Chapter 14, Problem 103QRT

Chapter 14 Solutions

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

Ch. 14.1 - Identify each molecule or ion as a Brnsted-Lowry...Ch. 14.1 - Using Le Chatelier’s Principle Use Le Chatelier’s...Ch. 14.1 - Prob. 14.3E Ch. 14.1 - Complete the table. Ch. 14.1 - Prob. 14.4E Ch. 14.1 - Prob. 14.5E Ch. 14.2 - Prob. 14.6CE Ch. 14.2 - Prob. 14.7E Ch. 14.3 - Prob. 14.2PSP Ch. 14.3 - Prob. 14.3PSP

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The p H of ocean’s surface water in the mid- 1800 s has to be calculated.

Solution Summary: The author explains that the pH of ocean’s surface water in the mid- 1800s is 8.2.

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Interpretation:

The pH of ocean’s surface water in the mid-1800s has to be calculated.

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Chapter 14 Solutions

The p H of ocean’s surface water in the mid- 1800 s has to be calculated.

Solution Summary: The author explains that the pH of ocean’s surface water in the mid- 1800s is 8.2.

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Interpretation: The pH of ocean’s surface water in the mid-1800s has to be calculated.

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Chapter 14 Solutions

Interpretation:

The pH of ocean’s surface water in the mid-1800s has to be calculated.