Explanation The addition of N a O C l to water results into a basic solution. The reaction is given below. O C l − ( a q ) + H 2 O ( l ) ⇌ H O C l ( a q ) + O H − ( a q ) The base ionization constant for the above equation can be written as given below. K b = [ H O C l ] [ O H − ] [ O C l − ] The concentration of H 3 O + can be calculated from the p H as given below. p H = − log [ H 3 O + ] ⇒ [ H 3 O + ] = 10 − p H = 10 − 5.50 = 3.2 × 10 − 6 . A table can be set up as given below. O C l − ( a q ) H O C l ( a q ) O H − ( a q ) I n i t i a l c o n c . ( M ) 0.010 0 1.0 × 10 − 7 C h a n g e i n c o n c . ( M ) − x + x + x E q u i l i b r i u m c o n c

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

5th Edition

ISBN: 9781285460420

Author: John W. Moore; Conrad L. Stanitski

Publisher: Cengage Learning US

See similar textbooks

Concept explainers

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibri…

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Videos

Question

Chapter 14, Problem 100QRT

Interpretation Introduction

Interpretation:

The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 14, Problem 99QRT

Chapter 14, Problem 101QRT

Students have asked these similar questions

A chemist dissolves 700. mg of pure sodium hydroxide in enough water to make up 60. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits. ☐ ×10

A chemist dissolves 134. mg of pure sodium hydroxide in enough water to make up 170. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits. x10 × S

Calculating the pH of a strong base solution 1/5 A chemist dissolves 706. mg of pure potassium hydroxide in enough water to make up 50. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Round your answer to 2 significant decimal places. ப ☐ x10 ☑

Chapter 14 Solutions

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

Ch. 14.1 - Identify each molecule or ion as a Brnsted-Lowry...Ch. 14.1 - Using Le Chatelier’s Principle Use Le Chatelier’s...Ch. 14.1 - Prob. 14.3E Ch. 14.1 - Complete the table. Ch. 14.1 - Prob. 14.4E Ch. 14.1 - Prob. 14.5E Ch. 14.2 - Prob. 14.6CE Ch. 14.2 - Prob. 14.7E Ch. 14.3 - Prob. 14.2PSP Ch. 14.3 - Prob. 14.3PSP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The p H of a 0.010 M solution of N a O C l ( K b = 1.5 × 10 − 7 ) has to be calculated.

Solution Summary: The author calculates the pH of a 0.010M solution of NaOClleft.

Concept explainers

Videos

Interpretation:

The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.

Want to see the full answer?

Chapter 14 Solutions

The p H of a 0.010 M solution of N a O C l ( K b = 1.5 × 10 − 7 ) has to be calculated.

Solution Summary: The author calculates the pH of a 0.010M solution of NaOClleft.

Concept explainers

Videos

Interpretation: The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.

Want to see the full answer?

Chapter 14 Solutions

Interpretation:

The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.