Explanation Milk of magnesia: The neutralization reaction of milk of magnesia with stomach acid is given below. M g ( O H ) 2 ( s ) + 2 H 3 O + ( a q ) → M g 2 + ( a q ) + 4 H 2 O ( l ) The molar ratio of antacid and the acid is 1 : 2. The moles of stomach acid that is neutralized by 1 g of milk of magnesia can be calculated as given below. 1 g M g ( O H ) 2 × 1 m o l M g ( O H ) 2 58.3196 g M g ( O H ) 2 × 2 m o l H 3 O + 1 m o l M g ( O H ) 2 = 0.03 m o l H 3 O + Calcium carbonate: The neutralization reaction of calcium carbonatewith stomach acid is given below. C a C O 3 ( s ) + 2 H 3 O + ( a q ) → C a 2 + ( a q ) + 3 H 2 O ( l ) + C O 2 ( g ) The molar ratio of antacid and the acid is 1 : 2. The moles of stomach acid that is neutralized by 1 g of calcium carbonate can be calculated as given below. 1 g C a C O 3 × 1 m o l C a C O 3 100.087 g C a C O 3 × 2 m o l H 3 O + 1 m o l C a C O 3 = 0.02 m o l H 3 O + Sodium hydrogen carbonate: The neutralization reaction of sodium hydrogen carbonatewith stomach acid is given below. N a H C O 3 ( s ) + H 3 O + ( a q ) → N a + ( a q ) + 2 H 2 O ( l ) + C O 2 ( g ) The molar ratio of antacid and the acid is 1 : 1. The moles of stomach acid that is neutralized by 1 g of sodium hydrogen carbonatecan be calculated as given below. 1 g N a H C O 3 × 1 m o l N a H C O 3 84.0066 g N a H C O 3 × 1 m o l H 3 O + 1 m o l N a H C O 3 = 0

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

5th Edition

ISBN: 9781285460420

Author: John W. Moore; Conrad L. Stanitski

Publisher: Cengage Learning US

See similar textbooks

Concept explainers

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibri…

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Videos

Question

Chapter 14, Problem 88QRT

Interpretation Introduction

Interpretation:

The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 14, Problem 87QRT

Chapter 14, Problem 89QRT

Students have asked these similar questions

Show work. don't give Ai generated solution. Don't copy the answer anywhere

6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?

Show work. don't give Ai

Chapter 14 Solutions

OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)

Ch. 14.1 - Identify each molecule or ion as a Brnsted-Lowry...Ch. 14.1 - Using Le Chatelier’s Principle Use Le Chatelier’s...Ch. 14.1 - Prob. 14.3E Ch. 14.1 - Complete the table. Ch. 14.1 - Prob. 14.4E Ch. 14.1 - Prob. 14.5E Ch. 14.2 - Prob. 14.6CE Ch. 14.2 - Prob. 14.7E Ch. 14.3 - Prob. 14.2PSP Ch. 14.3 - Prob. 14.3PSP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.

Solution Summary: The author explains the molar ratio of antacid and the acid is 1:2. The moles of stomach acid that is neutralized by 1g of calcium carbonate can be calculated.

Concept explainers

Videos

Interpretation: The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.

Want to see the full answer?

Chapter 14 Solutions

Interpretation:

The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.