Chapter 14.3, Problem 14.3PSP

Interpretation Introduction

Interpretation:

The hydroxide ion concentration in $6.0MHN{O}_3$ and hydronium ion concentration in $6.0MNaOH$ solution has to be calculated at $25{}^{o}C$.

Concept Introduction:

Ionic-product constant for water: It is the hydronium ion concentration times the $O{H}^{-}$ concentration present in the solution.

$\begin{array}{l}{H}_2{O}_{\left(l\right)}+H_2{O}_{\left(l\right)}{H}_3{O}^{+}{}_{\left(aq\right)}+O{H}^{-}{}_{\left(aq\right)}\\ K=\frac{\left[H_3{O}^{+}\right]\left[O{H}^{-}\right]}{\left[H_{2}O\right]\left[H_{2}O\right]}\\ \left[H_3{O}^{+}\right]=\left[O{H}^{-}\right]=1.00\times {10}^{-7}M\\ \therefore K_W=K\left[H_{2}O\right]\left[H_{2}O\right]=\left[H_3{O}^{+}\right]\left[O{H}^{-}\right]\\ K_W=1.00\times {10}^{-14}M\end{array}$

The hydroxide ion concentration in $6.0MHN{O}_3$ and hydronium ion concentration in $6.0MNaOH$ solution is calculated to be $\text{1}\text{.7×}{\text{10}}^{\text{-15}}\text{M}$.