EBK CHEMICAL PRINCIPLES
8th Edition
ISBN: 8220101425812
Author: DECOSTE
Publisher: Cengage Learning US
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Chapter 13, Problem 9DQ
Interpretation Introduction
Interpretation: The reason for the second
Concept Introduction: Electron affinity is defined as the amount of energy released when an electron is added to the outermost electronic shell of a neutral atom in the gaseous state to form a negatively charged ion.
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Use the following data to estimate AH; for sodium bromide.
Na(s) + Br2 (9) → NaBr(s)
Lattice energy
-742 kJ/mol
Ionization energy for Na
495 kJ/mol
-325 kJ/mol
Electron affinity of Br
Bond energy of Br2
Enthalpy of sublimation for Na
193 kJ/mol
109 kJ/mol
AH; = |
kJ/mol
Use the following data to estimate AH; for potassium bromide.
K(s) +
Br2 (9) - KBr(a)
Lattice energy
-671 kJ/mol
Ionization energy for K
419 kJ/mol
Electron affinity of Br
-325 kJ/mol
Bond energy of Br2
Enthalpy of sublimation for K
193 kJ/mol
90. kJ/mol
AH =
kJ/mol
The electron configurations for four main-group elements are given. Match the electron configuration on the left with the Lewis structure on the right.
Clear All
1s2s*2p*3s*3p²
4p*5s*4aU5p*
12s2p
:X:
Chapter 13 Solutions
EBK CHEMICAL PRINCIPLES
Ch. 13 - Explain the electronegativity trends across a row...Ch. 13 - Prob. 2DQCh. 13 - Prob. 3DQCh. 13 - Prob. 4DQCh. 13 - Prob. 5DQCh. 13 - Prob. 6DQCh. 13 - Prob. 7DQCh. 13 - Prob. 8DQCh. 13 - Prob. 9DQCh. 13 - Arrange the following molecules from most to least...
Ch. 13 - Prob. 11DQCh. 13 - Prob. 12DQCh. 13 - Prob. 13ECh. 13 - Prob. 14ECh. 13 - An alternative definition of electronegativity...Ch. 13 - Prob. 16ECh. 13 - Without using Fig. 13.3, predict the order of...Ch. 13 - Without using Fig. 13.3, predict which bond in...Ch. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 - Indicate the bond polarity (show the partial...Ch. 13 - Prob. 22ECh. 13 - Prob. 23ECh. 13 - Prob. 24ECh. 13 - Prob. 25ECh. 13 - Prob. 26ECh. 13 - Prob. 27ECh. 13 - Prob. 28ECh. 13 - Prob. 29ECh. 13 - Prob. 30ECh. 13 - Prob. 31ECh. 13 - Give an example of an ionic compound where both...Ch. 13 - What noble gas has the same electron configuration...Ch. 13 - Which of the following ions have noble gas...Ch. 13 - Give three ions that are isoelectronic with...Ch. 13 - Prob. 36ECh. 13 - Predict the empirical formulas of the ionic...Ch. 13 - Which compound in each of the following pairs of...Ch. 13 - Use the following data to estimate Hf for...Ch. 13 - Use the following data to estimate Hf for...Ch. 13 - Consider the following:...Ch. 13 - In general, the higher the charge on the ions in...Ch. 13 - Consider the following energy changes: a....Ch. 13 - Prob. 44ECh. 13 - Prob. 45ECh. 13 - The lattice energies of FeCl3,FeCl2,andFe2O3 are...Ch. 13 - Prob. 47ECh. 13 - Prob. 48ECh. 13 - Prob. 49ECh. 13 - Prob. 50ECh. 13 - Prob. 51ECh. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - Prob. 54ECh. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - Prob. 59ECh. 13 - Prob. 60ECh. 13 - Prob. 61ECh. 13 - Prob. 62ECh. 13 - Prob. 63ECh. 13 - Prob. 64ECh. 13 - Prob. 65ECh. 13 - Prob. 66ECh. 13 - Prob. 67ECh. 13 - Prob. 68ECh. 13 - Prob. 69ECh. 13 - Prob. 70ECh. 13 - Prob. 71ECh. 13 - Prob. 72ECh. 13 - Prob. 73ECh. 13 - Prob. 74ECh. 13 - Prob. 75ECh. 13 - Prob. 76ECh. 13 - Prob. 77ECh. 13 - Prob. 78ECh. 13 - Prob. 79ECh. 13 - Prob. 80ECh. 13 - Prob. 81ECh. 13 - Prob. 82ECh. 13 - Prob. 83ECh. 13 - Prob. 84ECh. 13 - Prob. 85ECh. 13 - Prob. 86ECh. 13 - Prob. 87ECh. 13 - Prob. 88ECh. 13 - Prob. 89ECh. 13 - Prob. 90ECh. 13 - Prob. 91ECh. 13 - Prob. 92ECh. 13 - Prob. 93ECh. 13 - Prob. 94ECh. 13 - Prob. 95ECh. 13 - Predict the molecular structure and the bond...Ch. 13 - Prob. 97ECh. 13 - Two variations of the octahedral geometry are...Ch. 13 - Prob. 99ECh. 13 - Predict the molecular structure and the bond...Ch. 13 - Which of the molecules in Exercise 96 have net...Ch. 13 - Prob. 102ECh. 13 - Give two requirements that should be satisfied for...Ch. 13 - What do each of the following sets of...Ch. 13 - Prob. 105ECh. 13 - Consider the following Lewis structure, where E is...Ch. 13 - Consider the following Lewis structure, where E is...Ch. 13 - Prob. 108ECh. 13 - Prob. 109ECh. 13 - Which of the following molecules have net dipole...Ch. 13 - Prob. 111AECh. 13 - Prob. 112AECh. 13 - Prob. 113AECh. 13 - Prob. 114AECh. 13 - Prob. 115AECh. 13 - There are two possible structures of XeF2Cl2 ,...Ch. 13 - Prob. 117AECh. 13 - Prob. 118AECh. 13 - Prob. 119AECh. 13 - Prob. 120AECh. 13 - Prob. 121AECh. 13 - Prob. 122AECh. 13 - Prob. 123AECh. 13 - Prob. 124AECh. 13 - Prob. 125AECh. 13 - Prob. 126AECh. 13 - Prob. 127AECh. 13 - Prob. 128AECh. 13 - Prob. 129AECh. 13 - Prob. 130AECh. 13 - Prob. 131AECh. 13 - Prob. 132AECh. 13 - Prob. 133CPCh. 13 - Prob. 134CPCh. 13 - Given the following information: Heat of...Ch. 13 - Prob. 136CPCh. 13 - A promising new material with great potential as...Ch. 13 - Think of forming an ionic compound as three steps...Ch. 13 - Prob. 139CPCh. 13 - Prob. 140CPCh. 13 - Calculate the standard heat of formation of the...Ch. 13 - Prob. 142CPCh. 13 - Prob. 143MP
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- "Inert" xenon actually forms several compounds, especially with the highly electronegative elements oxygen and fluorine. The simple fluorides XeF2, XeF4, and XeF, are all formed by direct reaction of the elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one. Calculate the Xe-F bond energy in XeF6, given that the heat of formation is -402 kJ/mol.arrow_forwardMatch each of the following Given the following information: N, bond energy = 941 kJ/mol , F, bond energy = 154 kJ/mol ½ N(a) + 3/2 F2c9) 2(g) NF, ' 3(g) AH = -103 kJ/mol 2(g) Choose... Calculate the N-F bond energy (kJ/mol) Choose... -37.6 39.0 268 -238.7 -48.25 A ballon originally had a volume of 8.68 L at 258 K and a pressure of 575 mmHg. To what temperature ( in K) must the balloon be cooled to reduce its volume to 5.00 L at a pressure of 730 mmHg? 188.7 11.85 10.7arrow_forwardCalculate the average A-B bond energy in AB3(g). AH for AB3(g)=-75.9 kJ/mol, AH, for A(g) = 288.9 kJ/mol, AH, for B(g) = 134.9 kJ/mol, AH for A2(g) = 0 kJ/mol, AH for B2(g)=0 kJ/mol. Enter a number in kJ/mol to 1 decimal place.arrow_forward
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