McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Question

Chapter 1.3, Problem 9CE

To determine

To find: The distance of RS in the given figure.

Expert Solution

Answer to Problem 9CE

The distance of RS is 1 unit.

Explanation of Solution

Given information: Consider the number line showing some points and there coordinates.

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.3, Problem 9CE , additional homework tip 1

Concept used: On a number line, the coordinate of a point is the value that the point represents. And using ruler postulate, distance between two points equals the absolute value of the difference between their coordinates.

Calculation: In number line shown, coordinate of point R is 0 and coordinate of point S is 1. So, using the ruler postulate,

RS=|1−0|=1

Conclusion: So, the distance of RS is 1 unit.

To determine

To find: The distance of RQ in the given figure.

Expert Solution

Answer to Problem 9CE

The distance of

RQ is 1 unit.

Explanation of Solution

Given information: Consider the number line showing some points and there coordinates.

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.3, Problem 9CE , additional homework tip 2

Calculation: In the number line shown, coordinate of point R is 0 and coordinate of point Q is −1 . So, using the ruler postulate,

RQ=|−1−0|=|−1|=1

Conclusion: So, the distance of RQ is 1unit.

To determine

To find: The distance of PT in the given figure.

Expert Solution

Answer to Problem 9CE

The distance of PT is 4 units.

Explanation of Solution

Given information: Consider the number line showing some points and there coordinates.

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.3, Problem 9CE , additional homework tip 3

Calculation: In shown number line, coordinate of point P is −2 and coordinate of point T is 2. So, using the ruler postulate,

PT=|−2−2|=|−4|=4

Conclusion: So, the distance of PT is 4 units.

Chapter 1.3, Problem 8CE

Chapter 1.3, Problem 10CE

Chapter 1 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 1.1 - Prob. 1CE Ch. 1.1 - Prob. 2CE Ch. 1.1 - Prob. 3CE Ch. 1.1 - Prob. 4CE Ch. 1.1 - Prob. 5CE Ch. 1.1 - Prob. 6CE Ch. 1.1 - Prob. 7CE Ch. 1.1 - Prob. 8CE Ch. 1.1 - Prob. 1WE Ch. 1.1 - Prob. 2WE

Ch. 1.1 - Prob. 3WE Ch. 1.1 - Prob. 4WE Ch. 1.1 - Prob. 5WE Ch. 1.1 - Prob. 6WE Ch. 1.1 - Prob. 7WE Ch. 1.1 - Prob. 8WE Ch. 1.1 - Prob. 9WE Ch. 1.1 - Prob. 10WE Ch. 1.2 - Prob. 1CE Ch. 1.2 - Prob. 2CE Ch. 1.2 - Prob. 3CE Ch. 1.2 - Prob. 4CE Ch. 1.2 - Prob. 5CE Ch. 1.2 - Prob. 6CE Ch. 1.2 - Prob. 7CE Ch. 1.2 - Prob. 8CE Ch. 1.2 - Prob. 9CE Ch. 1.2 - Prob. 10CE Ch. 1.2 - Prob. 11CE Ch. 1.2 - Prob. 12CE Ch. 1.2 - Prob. 13CE Ch. 1.2 - Prob. 14CE Ch. 1.2 - Prob. 15CE Ch. 1.2 - Prob. 16CE Ch. 1.2 - Prob. 17CE Ch. 1.2 - Prob. 18CE Ch. 1.2 - Prob. 19CE Ch. 1.2 - Prob. 20CE Ch. 1.2 - Prob. 1WE Ch. 1.2 - Prob. 2WE Ch. 1.2 - Prob. 3WE Ch. 1.2 - Prob. 4WE Ch. 1.2 - Prob. 5WE Ch. 1.2 - Prob. 6WE Ch. 1.2 - Prob. 7WE Ch. 1.2 - Prob. 8WE Ch. 1.2 - Prob. 9WE Ch. 1.2 - Prob. 10WE Ch. 1.2 - Prob. 11WE Ch. 1.2 - Prob. 12WE Ch. 1.2 - Prob. 13WE Ch. 1.2 - Prob. 14WE Ch. 1.2 - Prob. 15WE Ch. 1.2 - Prob. 16WE Ch. 1.2 - Prob. 17WE Ch. 1.2 - Prob. 18WE Ch. 1.2 - Prob. 19WE Ch. 1.2 - Prob. 20WE Ch. 1.2 - Prob. 21WE Ch. 1.2 - 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Prob. 14WE Ch. 1.5 - Prob. 15WE Ch. 1.5 - Prob. 16WE Ch. 1.5 - Prob. 17WE Ch. 1.5 - Prob. 18WE Ch. 1.5 - Prob. 19WE Ch. 1.5 - Prob. 20WE Ch. 1.5 - Prob. 1E Ch. 1.5 - Prob. 2E Ch. 1.5 - Prob. 3E Ch. 1.5 - Prob. 4E Ch. 1.5 - Prob. 5E Ch. 1.5 - Prob. 6E Ch. 1.5 - Prob. 1ST2 Ch. 1.5 - Prob. 2ST2 Ch. 1.5 - Prob. 3ST2 Ch. 1.5 - Prob. 4ST2 Ch. 1.5 - Prob. 5ST2 Ch. 1.5 - Prob. 6ST2 Ch. 1.5 - Prob. 7ST2 Ch. 1.5 - Prob. 8ST2 Ch. 1.5 - Prob. 9ST2 Ch. 1.5 - Prob. 10ST2 Ch. 1.5 - Prob. 11ST2 Ch. 1.5 - Prob. 12ST2 Ch. 1 - Prob. 1CR Ch. 1 - Prob. 2CR Ch. 1 - Prob. 3CR Ch. 1 - Prob. 4CR Ch. 1 - Prob. 5CR Ch. 1 - Prob. 6CR Ch. 1 - Prob. 7CR Ch. 1 - Prob. 8CR Ch. 1 - Prob. 9CR Ch. 1 - Prob. 10CR Ch. 1 - Prob. 11CR Ch. 1 - Prob. 12CR Ch. 1 - Prob. 13CR Ch. 1 - Prob. 14CR Ch. 1 - Prob. 15CR Ch. 1 - Prob. 16CR Ch. 1 - Prob. 17CR Ch. 1 - Prob. 18CR Ch. 1 - Prob. 19CR Ch. 1 - Prob. 20CR Ch. 1 - Prob. 1CT Ch. 1 - Prob. 2CT Ch. 1 - Prob. 3CT Ch. 1 - Prob. 4CT Ch. 1 - Prob. 5CT Ch. 1 - Prob. 6CT Ch. 1 - Prob. 7CT Ch. 1 - 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The distance of R S in the given figure.

Concept explainers

Videos

To find: The distance of RS in the given figure.

Answer to Problem 9CE

Explanation of Solution

To find: The distance of RQ in the given figure.

Answer to Problem 9CE

Explanation of Solution

To find: The distance of PT in the given figure.

Answer to Problem 9CE

Explanation of Solution

Chapter 1 Solutions

Additional Math Textbook Solutions