McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 1.2, Problem 31AR

To determine

To find: The value of the variable from the equation (2g−15)+g=9 .

Expert Solution & Answer

Answer to Problem 31AR

The value of the variable is g=8 .

Explanation of Solution

Given:

The equation is (2g−15)+g=9 .

Calculation:

Simplify the equation (2g−15)+g=9 as follows:

(2g−15)+g=92g+g−15=93g−15+15=9+153g=243g3=243g=8

Thus, the value of the variable is g=8 .

Chapter 1.2, Problem 30AR

Chapter 1.2, Problem 32AR

Chapter 1 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 1.1 - Prob. 1CE Ch. 1.1 - Prob. 2CE Ch. 1.1 - Prob. 3CE Ch. 1.1 - Prob. 4CE Ch. 1.1 - Prob. 5CE Ch. 1.1 - Prob. 6CE Ch. 1.1 - Prob. 7CE Ch. 1.1 - Prob. 8CE Ch. 1.1 - Prob. 1WE Ch. 1.1 - Prob. 2WE

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The value of the variable from the equation ( 2 g − 15 ) + g = 9 .