McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Question

Chapter 1.2, Problem 31AR

To determine

To find: The value of the variable from the equation (2g−15)+g=9 .

Expert Solution & Answer

Answer to Problem 31AR

The value of the variable is g=8 .

Explanation of Solution

Given:

The equation is (2g−15)+g=9 .

Calculation:

Simplify the equation (2g−15)+g=9 as follows:

(2g−15)+g=92g+g−15=93g−15+15=9+153g=243g3=243g=8

Thus, the value of the variable is g=8 .

Chapter 1.2, Problem 30AR

Chapter 1.2, Problem 32AR

Chapter 1 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

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