Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 13, Problem 16QLP
Explain why the rolling process was invented and developed.
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Plot the displacement diagram for a cam with roller follower of diameter 10 mm. The required
motion is as follows;
1- Rising 60 mm in 135° with uniform acceleration and retardation motion.
2- Dwell 90°
3- Falling 60 mm for 135° with Uniform acceleration-retardation motion.
Then design the cam profile to give the above displacement diagram if the minimum circle
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Chapter 13 Solutions
Manufacturing Engineering & Technology
Ch. 13 - What is the difference between a plate and a...Ch. 13 - Define roll gap, neutral point, and draft.Ch. 13 - What factors contribute to spreading in flat...Ch. 13 - What is forward slip? Why is it important?Ch. 13 - Describe the types of deflections that rolls...Ch. 13 - Describe the difference between a bloom, a slab,...Ch. 13 - Why may roller leveling be a necessary operation?Ch. 13 - List the defects commonly observed in flat...Ch. 13 - What are the advantages of tandem rolling? Pack...Ch. 13 - How are seamless tubes produced?
Ch. 13 - Why is the surface finish of a rolled product...Ch. 13 - What is a Sendzimir mill? What are its important...Ch. 13 - What is the Mannesmann process? How is it...Ch. 13 - Describe ring rolling. Is there a neutral plane in...Ch. 13 - How is back tension generated?Ch. 13 - Explain why the rolling process was invented and...Ch. 13 - Flat rolling reduces the thickness of plates and...Ch. 13 - Explain how the residual stress patterns shown in...Ch. 13 - Explain whether it would be practical to apply the...Ch. 13 - Describe the factors that influence the magnitude...Ch. 13 - Explain how you would go about applying front and...Ch. 13 - What typically is done to make sure that the...Ch. 13 - Make a list of parts that can be made by (a) shape...Ch. 13 - Describe the methods by which roll flattening can...Ch. 13 - It was stated that spreading in flat rolling...Ch. 13 - Flat rolling can be carried out by front tension...Ch. 13 - Explain the consequence of applying too high a...Ch. 13 - Note in Fig. 13.3f that the driven rolls (powered...Ch. 13 - Describe the importance of controlling roll...Ch. 13 - In Fig. 13.9a, if you remove the top compressive...Ch. 13 - Name several products that can be made by each of...Ch. 13 - List the possible consequences of rolling at (a)...Ch. 13 - It is known that in thread rolling, as illustrated...Ch. 13 - If a rolling mill encounters chatter, what process...Ch. 13 - Can the forward slip ever become negative? Why or...Ch. 13 - In Example 13.1, calculate the roll force and the...Ch. 13 - Calculate the individual drafts in each of the...Ch. 13 - Estimate the roll force, F, and the torque for an...Ch. 13 - A rolling operation takes place under the...Ch. 13 - Estimate the roll force and power for annealed...Ch. 13 - A flat-rolling operation is being carried out...Ch. 13 - A simple sketch of a four-high mill stand is shown...Ch. 13 - Obtain a piece of soft, round rubber eraser, such...Ch. 13 - If you repeat the experiment in Problem 13.45 with...Ch. 13 - Design a set of rolls to produce cross-sections...Ch. 13 - Design an experimental procedure for determining...Ch. 13 - Derive an expression for the thickest workpiece...
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- I need handwritten solution with sketches for eacharrow_forwardGiven answers to be: i) 14.65 kN; 6.16 kN; 8.46 kN ii) 8.63 kN; 9.88 kN iii) Bearing 6315 for B1 & B2, or Bearing 6215 for B1arrow_forward(b) A steel 'hot rolled structural hollow section' column of length 5.75 m, has the cross-section shown in Figure Q.5(b) and supports a load of 750 kN. During service, it is subjected to axial compression loading where one end of the column is effectively restrained in position and direction (fixed) and the other is effectively held in position but not in direction (pinned). i) Given that the steel has a design strength of 275 MN/m², determine the load factor for the structural member based upon the BS5950 design approach using Datasheet Q.5(b). [11] ii) Determine the axial load that can be supported by the column using the Rankine-Gordon formula, given that the yield strength of the material is 280 MN/m² and the constant *a* is 1/30000. [6] 300 600 2-300 mm wide x 5 mm thick plates. Figure Q.5(b) L=5.75m Pinned Fixedarrow_forward
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