(a) Explanation Given information: In level pavement, the breaking distance of automobile at 108 km/h is 75 m. Calculation: Write equation of motion for the velocity of automobile: v f 2 = v 0 2 + 2 a S Here, v f is the final velocity of the automobile, v 0 is the initial velocity of the automobile, a is the acceleration of the automobile, and S is the distance travelled or the difference between the initial and final position of the automobile after the breaks apply. Substitute ( x f − x 0 ) for S . v f 2 = v 0 2 + 2 a ( x f − x 0 ) (1) Here, x f is the final position of the automobile and x 0 is the initial position of the automobile. Find the acceleration of the automobile on the level surface using Equation (1): v f 2 = v 0 2 + 2 a ( x f − x 0 ) Substitute 0 for x 0 , 0 for v f , 108 km / h for v 0 , and 75m for x f . v 2 = v 0 2 + 2 a ( x f − x i ) 0 = ( 108 km h × 1,000 m 1km × 1h 3,600 s ) 2 + 2 a ( 75 − 0 ) 150 a = − 900 a = − 6 m/s 2 Write the Equation of mass ( m ): W = m g m = W g Here, W is the weight of automobile, g is the acceleration due to gravity. Find the braking force ( F b ) using Newton’s law of motion: F b = m a Substitute W g for m . F b = W g a Substitute − 6 m / s 2 for a and 9.81 m / s 2 for g . F b = W 9.81 ( − 6 ) = − 0 (b) To determine Find the automobile’s braking distance when it is going down 3-percent incline.

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Author: BEER

Publisher: MCG

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Chapter 12.1, Problem 12.9P

(a)

To determine

Find the automobile’s braking distance when it is going up a 5 degree incline.

(b)

To determine

Find the automobile’s braking distance when it is going down 3-percent incline.

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Chapter 12.1, Problem 12.8P

Chapter 12.1, Problem 12.10P

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Find the automobile’s braking distance when it is going up a 5 degree incline.

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Find the automobile’s braking distance when it is going up a 5 degree incline.

Find the automobile’s braking distance when it is going down 3-percent incline.

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