(a)
Interpretation: The products of the given reaction have to be found.
Concept Introduction:
Grignard reaction with
Grignard regent reacts with ketone followed by acidic work up to form secondary or tertiary alcohol.
General scheme:
(b)
Interpretation: The products of the given reaction have to be found.
Concept Introduction:
Hemiketals:
Hemiaketals are compounds with the
General scheme:
(c)
Interpretation: The products of the given reaction have to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
(d)
Interpretation: The products of the given reaction have to be found.
Concept Introduction:
Major product in the reaction of
General scheme:
It can be observed that the conjugate addition product has been formed by the addition of basic anion to the beta-carbon atom and that of hydrogen atom to the alpha-carbon carbon atom.
The examples for the weak bases are:
Major product in the reaction of
General scheme:
It can be observed that the direct addition product has been formed from the direct reaction of the strong base with the carbonyl functional group of the
The examples for the strong bases are:
Aminolysis reaction:
- The aminolysis reaction is just like hydrolysis in which one component gets converted into two components using a molecule of amine like using a molecule of water in hydrolysis.
- In the aminolysis of ester, one ester component reacts with a molecule of amine and will be converted into two components such as an amide and an alcohol which has been shown in the following general scheme:
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Chapter 12 Solutions
EP ESSENTIAL ORG.CHEM.-MOD.MASTERING
- Redraw the flowchartarrow_forwardredraw the flowchart with boxes and molecules written in themarrow_forwardPart I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward
- • Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forwardNonearrow_forward
- Draw the curved-arrow mechanism with the drawings of the molecules, not just abbreviations. -NO₂ Sn, HCl (aq) E D H (CH3CO)₂O -NH2 CH3arrow_forwardWhat is/are the product(s) of the following reaction? Select all that apply. * HI A B C OD OH A B OH D Carrow_forwardIn the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+. Assuming there is 2.00 L of solution, answer the following: The Ka of the left & right solution is? The pH of the left & right solution is? The acid on the left & right is what kind of acid?arrow_forward
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