Explanation Given: The given circuit is shown in Figure 1. Calculation: Break the feedback loop and draw the equivalent resistance of the above circuit. The given diagrams is shown in Figure 2 From the above circuit the expression for the input current is given by, I i = I ε Apply KCL at the output side. A i I i + V O R 1 + V O R F + ( R S | | R S ) = 0 ……. (1) The expression for the current I r is given by, I r = ( R R S + R i ) V O R F + ( R S | | R S ) V O = ( R S + R i R S ) ( R F + ( R S | | R S ) ) I r Substitute ( R S + R i R S ) ( R F + ( R S | | R S ) ) I r for V O in the above equation

Microelectronics: Circuit Analysis and Design

4th Edition

ISBN: 9780073380643

Author: Donald A. Neamen

Publisher: McGraw-Hill Companies, The

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Chapter 12, Problem 12.68P

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The expression for the loop gain.

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Chapter 12, Problem D12.67P

Chapter 12, Problem 12.69P

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Chapter 12 Solutions

Microelectronics: Circuit Analysis and Design

Ch. 12 - (a) The open-loop gain of an amplifier is A=5104...Ch. 12 - (a) Consider a general feedback system with...Ch. 12 - (a) A feedback amplifier has an open-loop...Ch. 12 - (a) Consider the circuit shown in Figure...Ch. 12 - (a) The closed-loop gain of a feedback amplifier...Ch. 12 - The gain factors in a feedback system are A=5105...Ch. 12 - Prob. 12.3TYU Ch. 12 - An ideal series-shunt feedback amplifier is shown...Ch. 12 - Consider the ideal shunt-series feedback amplifier...Ch. 12 - An ideal series-series feedback amplifier is shown...

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The expression for the loop gain.

Solution Summary: The author explains the expression for the loop gain, which is -A_ileft.

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Chapter 12 Solutions