Explanation Given: The given circuit is shown in Figure 1 The closed loop voltage gain is − 5 Calculation: The required diagram for the three stage cascade feedback shunt-shunt circuit is shown below. The equivalent resistance of the circuit is calculated as, R T H = ( 4 k Ω ) ( 15 k Ω ) ( 4 k Ω ) + ( 15 k Ω ) = 3.16 k Ω The Thevenin voltage is calculated as, V T H = ( 4 k Ω 4 k Ω + 15 k Ω ) ( 12 V ) = 2.526 V The expression to determine the value of the base quiescent current is given by, I B Q = V T H − V B E ( o n ) R T h + ( 1 + h F E ) R E Substitute 2.526 V for V T H , 0.7 V for V B E ( o n ) , 4 k Ω for R E and 180 for h F E and 3.16 k Ω for R T H in the above equation. I B Q = 2.526 V − 0.7 V 3.16 k Ω + ( 1 + 180 ) 4 k Ω = 0.00251 mA The expression to determine the value of the collector quiescent current is given by, I C Q = h F E I B Q Substitute 180 for h F E and 0.00251 mA for I B Q in the above equation. I C Q = ( 180 ) ( 0.00251 mA ) = 0.452 mA The expression to determine the value of the transconductance is given bt, g m = I C Q V T Substitute 0.452 mA for I C Q and 0.026 V for V T in the above equation. g m = 0.80.452 mA 34 mA 0.026 V = 17.38 mA / V The expression to determine the value of the small signal resistance is given by, r π = h F E g m Substitute 180 for h F E and 17.38 mA / V for g m in the above equation. r π = 180 17.38 mA / V = 10.35 k Ω The expression for the small signal model of the given circuit is shown in Figure 2 The required diagram is shown in Figure 2 Apply KCL at node V π 1 . V i − V π 1 R S + V π 1 R B | | r π + V π 1 − V O R F = 0 Substitute 10 for R S . 3.16 k Ω for R B , 10.35 k Ω for r π in the above equation. V i − V π 1 10 k Ω + V π 1 3.16 k Ω | | 10.35 k Ω + V π 1 − V O R F = 0 0.1 m ( V i ) = V π 1 ( 0.513 m + 1 R F ) − V O R F ……. (1) Apply KCL at node V π 2 . g m V π 1 + V π 2 R C | | R B | | r π = 0 Substitute 17.38 mA / V for g m , 8 k Ω for R C , 3.16 k Ω for R B , 10.35 k Ω for r π in the above equation. ( 17.38 mA / V ) V π 1 + V π 2 8 k Ω | | 3

Microelectronics: Circuit Analysis and Design

4th Edition

ISBN: 9780073380643

Author: Donald A. Neamen

Publisher: McGraw-Hill Companies, The

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Chapter 12, Problem 12.65P

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Chapter 12 Solutions

Microelectronics: Circuit Analysis and Design

Ch. 12 - (a) The open-loop gain of an amplifier is A=5104...Ch. 12 - (a) Consider a general feedback system with...Ch. 12 - (a) A feedback amplifier has an open-loop...Ch. 12 - (a) Consider the circuit shown in Figure...Ch. 12 - (a) The closed-loop gain of a feedback amplifier...Ch. 12 - The gain factors in a feedback system are A=5105...Ch. 12 - Prob. 12.3TYU Ch. 12 - An ideal series-shunt feedback amplifier is shown...Ch. 12 - Consider the ideal shunt-series feedback amplifier...Ch. 12 - An ideal series-series feedback amplifier is shown...

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The value of the resistance R F for the given specifications.

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The value of the resistance RF for the given specifications.

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Chapter 12 Solutions