Chapter 12, Problem 12.59P

Interpretation Introduction

(a)

Interpretation: The product of given asymmetric epoxidation reaction is to be drawn.

Concept introduction: Sharpless epoxidation involves the oxidation of double bond between carbon atoms to form an epoxide. This oxidation occurs only in allylic alcohol. This is an enantioselective oxidation, which means predominantly one enantiomer is formed. Sharpless reagents are $tert\text{-butyl}\text{hydroperoxide,}{\left({\text{CH}}_{\text{3}}\right)}_{\text{3}}\text{COOH}$; titanium $\left(\text{IV}\right)$ isopropoxide, $\text{Ti}{\left[\text{OCH}{\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\right]}_{\text{4}}$; and diethyl tartrate.

Interpretation Introduction

(b)

Interpretation: The product of given asymmetric epoxidation reaction is to be drawn.

Concept introduction: Sharpless epoxidation involves the oxidation of double bond between carbon atoms to epoxide. This oxidation occurs only in allylic alcohol. This is an enantioselective oxidation, which means predominantly one enantiomer is formed. Sharpless reagents are $tert\text{-butyl}\text{hydroperoxide,}{\left({\text{CH}}_{\text{3}}\right)}_{\text{3}}\text{COOH}$; titanium $\left(\text{IV}\right)$ isopropoxide, $\text{Ti}{\left[\text{OCH}{\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\right]}_{\text{4}}$; and diethyl tartrate.