Consider the following system: 4 NH 3 ( g ) + 3 O 2 ( g ) ⇄ N 2 ( g ) + 6 H 2 O ( l ) Δ H = − 153 0. 4 kJ (a) How will the amount of ammonia at equilibrium be affected by (1) removing O 2 (g) (2) adding N 2 (g)? (3) adding water? (4) expanding the container at constant pressure? (5) increasing the temperature? (b) Which of the above factors will increase the value of K? Which will decrease it?
Consider the following system: 4 NH 3 ( g ) + 3 O 2 ( g ) ⇄ N 2 ( g ) + 6 H 2 O ( l ) Δ H = − 153 0. 4 kJ (a) How will the amount of ammonia at equilibrium be affected by (1) removing O 2 (g) (2) adding N 2 (g)? (3) adding water? (4) expanding the container at constant pressure? (5) increasing the temperature? (b) Which of the above factors will increase the value of K? Which will decrease it?
Solution Summary: The author explains that if oxygen is removed, nitrogen is added, water is expanded, and temperature is increased, the reaction favours a forward reaction.
For the compound: C8H17NO2
Use the following information to come up with a plausible structure:
8
This compound has "carboxylic acid amide" and ether functional groups.
The peaks at 1.2ppm are two signals that are overlapping one another.
One of the two signals is a doublet that represents 6 hydrogens; the
other signal is a quartet that represents 3 hydrogens.
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Please help me find the 1/Time, Log [I^-] Log [S2O8^2-], Log(time) on the data table. With calculation steps. And the average for runs 1a-1b. Please help me thanks in advance. Will up vote!
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Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY