Chapter 12, Problem 105A

(a)

Interpretation Introduction

Interpretation: The net ionic for the equation $\text{Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(aq\right)+{\text{Na}}_2{\text{SO}}_4\left(aq\right)\to {\text{BaSO}}_4\left(s\right)+{\text{NaNO}}_3\left(aq\right)$ is to be written.

Concept Introduction: Dissolved ionic substances are represented as dissociated free ions in the ionic equation. The net ionic equation does not involve the spectator ions.

Answer to Problem 105A

The net ionic equation is as follows:

  ${\text{Ba}}^{2+}\left(aq\right)+{\text{SO}}_4^{2-}\left(aq\right)\to {\text{BaSO}}_4\left(s\right)$

Explanation of Solution

The given chemical equation is as follows:

  $\text{Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(aq\right)+{\text{Na}}_2{\text{SO}}_4\left(aq\right)\to {\text{BaSO}}_4\left(s\right)+{\text{NaNO}}_3\left(aq\right)$

The balanced chemical equation is as follows:

  $\text{Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(aq\right)+{\text{Na}}_2{\text{SO}}_4\left(aq\right)\to {\text{BaSO}}_4\left(s\right)+2{\text{NaNO}}_3\left(aq\right)$

The ionic equation is as follows:

  ${\text{Ba}}^{2+}\left(aq\right){\text{+2NO}}_3^{-}\left(aq\right)+2{\text{Na}}^{+}\left(aq\right)+{\text{SO}}_4^{2-}\left(aq\right)\to {\text{BaSO}}_4\left(s\right)+2{\text{Na}}^{+}\left(aq\right)+{\text{2NO}}_3^{-}\left(aq\right)$

  ${\text{Na}}^{+}$ and ${\text{NO}}_3^{-}$ are spectator ions since they appear on both sides of an equation and are not directly involved in the chemical reaction.

The net ionic equation is as follows:

  ${\text{Ba}}^{2+}\left(aq\right)+{\text{SO}}_4^{2-}\left(aq\right)\to {\text{BaSO}}_4\left(s\right)$

(b)

Interpretation Introduction

Interpretation: The net ionic for the equation ${\text{AlCl}}_3\left(aq\right)+{\text{AgNO}}_3\left(aq\right)\to \text{AgCl}\left(s\right)+\text{Al}{\left({\text{NO}}_3\right)}_3\left(aq\right)$ is to be written.

Concept Introduction: Dissolved ionic substances are represented as dissociated free ions in the ionic equation. The net ionic equation does not involve the spectator ions.

Answer to Problem 105A

The net ionic equation is as follows:

  $3{\text{Cl}}^{-}\left(aq\right)+3{\text{Ag}}^{+}\left(aq\right)+\to 3\text{AgCl}\left(s\right)$

Explanation of Solution

The given chemical equation is as follows:

  ${\text{AlCl}}_3\left(aq\right)+{\text{AgNO}}_3\left(aq\right)\to \text{AgCl}\left(s\right)+\text{Al}{\left({\text{NO}}_3\right)}_3\left(aq\right)$

The balanced chemical equation is as follows:

  ${\text{AlCl}}_3\left(aq\right)+3{\text{AgNO}}_3\left(aq\right)\to 3\text{AgCl}\left(s\right)+\text{Al}{\left({\text{NO}}_3\right)}_3\left(aq\right)$

The ionic equation is as follows:

  ${\text{Al}}^{3+}\left(aq\right)+3{\text{Cl}}^{-}\left(aq\right)+3{\text{Ag}}^{+}\left(aq\right)+3{\text{NO}}_3^{-}\left(aq\right)\to 3\text{AgCl}\left(s\right)+{\text{Al}}^{3+}\left(aq\right)+3{\text{NO}}_3^{-}\left(aq\right)$

  ${\text{Al}}^{3+}$ and ${\text{NO}}_3^{-}$ are spectator ions since they appear on both sides of an equation and are not directly involved in the chemical reaction.

The net ionic equation is as follows:

  $3{\text{Cl}}^{-}\left(aq\right)+3{\text{Ag}}^{+}\left(aq\right)+\to 3\text{AgCl}\left(s\right)$

(c)

Interpretation Introduction

Interpretation: The net ionic for the equation ${\text{H}}_2{\text{SO}}_4\left(aq\right)+\text{Mg}{\left(\text{OH}\right)}_2\left(aq\right)\to {\text{MgSO}}_4\left(aq\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)$ is to be written.

Concept Introduction: Dissolved ionic substances are represented as dissociated free ions in the ionic equation. The net ionic equation does not involve the spectator ions.

Answer to Problem 105A

The net ionic equation is as follows:

  ${\text{2H}}^{+}\left(aq\right)+2{\text{OH}}^{-}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)$

Explanation of Solution

The given chemical equation is as follows:

  ${\text{H}}_2{\text{SO}}_4\left(aq\right)+\text{Mg}{\left(\text{OH}\right)}_2\left(aq\right)\to {\text{MgSO}}_4\left(aq\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)$

The balanced chemical equation is as follows:

  ${\text{H}}_2{\text{SO}}_4\left(aq\right)+\text{Mg}{\left(\text{OH}\right)}_2\left(aq\right)\to {\text{MgSO}}_4\left(aq\right)+2{\text{H}}_{\text{2}}\text{O}\left(l\right)$

The ionic equation is as follows:

  ${\text{2H}}^{+}\left(aq\right)+{\text{SO}}_4^{2-}\left(aq\right)+{\text{Mg}}^{2+}\left(aq\right)+2{\text{OH}}^{-}\left(aq\right)\to {\text{Mg}}^{2+}\left(aq\right)+{\text{SO}}_4^{2-}\left(aq\right)+2{\text{H}}_{\text{2}}\text{O}\left(l\right)$

  ${\text{Mg}}^{2+}$ and ${\text{SO}}_4^{2-}$ are spectator ions since they appear on both sides of an equation and are not directly involved in the chemical reaction.

The net ionic equation is as follows:

  ${\text{2H}}^{+}\left(aq\right)+2{\text{OH}}^{-}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)$