Chapter 12, Problem 103A

(a)

Interpretation Introduction

Interpretation: A balanced chemical equation for the lead(II) nitrate decomposition on heating produces lead(II) oxide, oxygen molecules, and nitrogen dioxide is to be written.

Concept Introduction: The components of a chemical equation are reactants, products, and a directional arrow. For a chemical reaction to be considered "balanced," both sides of the equation must have the same number of atoms.

Answer to Problem 103A

The balanced chemical equation is as follows:

  $\text{2Pb}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(s\right)\to 2\text{PbO}\left(s\right)+4{\text{NO}}_2\left(g\right)+{\text{O}}_2\left(g\right)$

Explanation of Solution

Lead(II) nitrate decomposition on heating produces lead(II) oxide, oxygen molecules, and nitrogen dioxide.

The chemical reaction is as follows:

  $\text{Pb}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(s\right)\to \text{PbO}\left(s\right)+{\text{NO}}_2\left(g\right)+{\text{O}}_2\left(g\right)$

The balanced chemical equation is as follows:

  $\text{2Pb}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(s\right)\to 2\text{PbO}\left(s\right)+4{\text{NO}}_2\left(g\right)+{\text{O}}_2\left(g\right)$

(b)

Interpretation Introduction

Interpretation: A balanced chemical equation for the combustion of isopropyl alcohol to produce water vapor and carbon dioxide is to be written.

Concept Introduction: The components of a chemical equation are reactants, products, and a directional arrow. For a chemical reaction to be considered "balanced," both sides of the equation must have the same number of atoms.

Answer to Problem 103A

The balanced chemical equation is as follows:

  ${\text{2C}}_{\text{3}}{\text{H}}_{\text{7}}\text{OH}\left(l\right)+9{\text{O}}_2\left(g\right)\to 6{\text{CO}}_2\left(g\right)+8{\text{H}}_2\text{O}\left(g\right)$

Explanation of Solution

Combustion of isopropyl alcohol produces carbon dioxide and water vapor.

The chemical reaction is as follows:

  ${\text{C}}_{\text{3}}{\text{H}}_{\text{7}}\text{OH}\left(l\right)+{\text{O}}_2\left(g\right)\to {\text{CO}}_2\left(g\right)+{\text{H}}_2\text{O}\left(g\right)$

The balanced chemical equation is as follows:

  ${\text{2C}}_{\text{3}}{\text{H}}_{\text{7}}\text{OH}\left(l\right)+9{\text{O}}_2\left(g\right)\to 6{\text{CO}}_2\left(g\right)+8{\text{H}}_2\text{O}\left(g\right)$

(c)

Interpretation Introduction

Interpretation: A balanced chemical equation for a mixture of aluminum and iron(II) oxide heated to produce aluminum oxide and metallic iron is to be written.

Concept Introduction: The components of a chemical equation are reactants, products, and a directional arrow. For a chemical reaction to be considered "balanced," both sides of the equation must have the same number of atoms.

Answer to Problem 103A

The balanced chemical equation is as follows:

  $\text{2Al}\left(s\right)+3\text{FeO}\left(s\right)\to 3\text{Fe}\left(s\right)+{\text{Al}}_2{\text{O}}_3\left(s\right)$

Explanation of Solution

When heated, a mixture of aluminum and iron(II) oxide produces aluminum oxide and metallic iron.

The chemical reaction is as follows:

  $\text{Al}\left(s\right)+\text{FeO}\left(s\right)\to \text{Fe}\left(s\right)+{\text{Al}}_2{\text{O}}_3\left(s\right)$

The balanced chemical equation is as follows:

  $\text{2Al}\left(s\right)+3\text{FeO}\left(s\right)\to 3\text{Fe}\left(s\right)+{\text{Al}}_2{\text{O}}_3\left(s\right)$