The formation of alkene 2-phenyl-2-butene is E or Z has to be explained from tosylate of (2R,3R)-3-phenyl-2-butanol via E2 elimination, similarly, the formation of alkene 2-phenyl-2-butene is E or Z has to be explained from tosylate of (2S,3R) and (2S,3S) tosylates -3-phenyl-2-butanol via E2 elimination. Concept introduction: Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction. E2 elimination: Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step. Given information: The given compound is shown below,

Question

In the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,

Answer 1

Question

Chapter 11.SE, Problem 65AP

Interpretation Introduction

Interpretation:

The formation of alkene 2-phenyl-2-butene is E or Z has to be explained from tosylate of (2R,3R)-3-phenyl-2-butanol via E2 elimination, similarly, the formation of alkene 2-phenyl-2-butene is E or Z has to be explained from tosylate of (2S,3R) and (2S,3S) tosylates -3-phenyl-2-butanol via E2 elimination.

Concept introduction:

Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.

E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the Î²-carbon atom followed by elimination of the bromine in a single step.

Given information:

The given compound is shown below,

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Part V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0