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a)
Interpretation:
The given molecule has to be prepared by using nucleophilic substitution reaction.
Concept introduction:
SN1 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid which yield the corresponding carbocation intermediate, this carbocation intermediate undergoes substitution reaction which yields the corresponding substitution product.
Tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation.
Primary alcohol is less stable therefore it won’t undergo SN1substitution reaction.
SN2 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid, the bromine atom attacks back side of the carbon atoms in simultaneous manner and which is bearing alcohol group which yield the corresponding product.
Example:
Alcohol is reaction with tosyl chloride in pyridine which provides retention of configuration of tosylated compound. This tosylated compound is further reaction with sodium methoxide which undergoes again SN2 type of reaction, the methoxide ion attacks the carbon atom through the back side and provides Inverse configuration of methoxy compound. This is shown below,
SN2 reaction is second order
![Check Mark](/static/check-mark.png)
Answer to Problem 45AP
The reaction is given below,
Explanation of Solution
Given information:
The product of the reaction is given below,
The reaction is given below,
The sodium amide is acts as a base and it abstract the highly acidic proton from propylene gives carbanion, this carbanion react with 2-bromo propane gives the corresponding product.
The given molecule is prepared by using nucleophilic substitution reaction.
b)
Interpretation:
The given molecule has to be prepared by using nucleophilic substitution reaction.
Concept introduction:
SN1 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid which yield the corresponding carbocation intermediate, this carbocation intermediate undergoes substitution reaction which yields the corresponding substitution product.
Tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation.
Primary alcohol is less stable therefore it won’t undergo SN1substitution reaction.
SN2 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid, the bromine atom attacks back side of the carbon atoms in simultaneous manner and which is bearing alcohol group which yield the corresponding product.
Example:
Alcohol is reaction with tosyl chloride in pyridine which provides retention of configuration of tosylated compound. This tosylated compound is further reaction with sodium methoxide which undergoes again SN2 type of reaction, the methoxide ion attacks the carbon atom through the back side and provides Inverse configuration of methoxy compound. This is shown below,
SN2 reaction is second order reaction, the rate of the reaction is depending on the both substrate and nucleophiles.
![Check Mark](/static/check-mark.png)
Answer to Problem 45AP
The reaction is given below,
Explanation of Solution
Given information:
The product of the reaction is given below,
The reaction is given below,
The sodium tertiary butoxide is acts as a base and it react with methyl bromide gives the corresponding ether product.
The given molecule is prepared by using nucleophilic substitution reaction.
c)
Interpretation:
The given molecule has to be prepared by using nucleophilic substitution reaction.
Concept introduction:
SN1 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid which yield the corresponding carbocation intermediate, this carbocation intermediate undergoes substitution reaction which yields the corresponding substitution product.
Tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation.
Primary alcohol is less stable therefore it won’t undergo SN1substitution reaction.
SN2 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid, the bromine atom attacks back side of the carbon atoms in simultaneous manner and which is bearing alcohol group which yield the corresponding product.
Example:
Alcohol is reaction with tosyl chloride in pyridine which provides retention of configuration of tosylated compound. This tosylated compound is further reaction with sodium methoxide which undergoes again SN2 type of reaction, the methoxide ion attacks the carbon atom through the back side and provides Inverse configuration of methoxy compound. This is shown below,
SN2 reaction is second order reaction, the rate of the reaction is depending on the both substrate and nucleophiles.
![Check Mark](/static/check-mark.png)
Answer to Problem 45AP
The reaction is given below,
Explanation of Solution
Given information:
The product of the reaction is given below,
The reaction is given below,
n-butyl bromide undergoes nucleophilic substitution reaction with cyanide (sodium cyanide) gives the corresponding cyanide product.
The given molecule is prepared by using nucleophilic substitution reaction.
d)
Interpretation:
The given molecule has to be prepared by using nucleophilic substitution reaction.
Concept introduction:
SN1 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid which yield the corresponding carbocation intermediate, this carbocation intermediate undergoes substitution reaction which yields the corresponding substitution product.
Tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation.
Primary alcohol is less stable therefore it won’t undergo SN1substitution reaction.
SN2 reaction:
The alcohol is reaction with acids like hydrochloric acid or hydrobromic acid, the bromine atom attacks back side of the carbon atoms in simultaneous manner and which is bearing alcohol group which yield the corresponding product.
Example:
Alcohol is reaction with tosyl chloride in pyridine which provides retention of configuration of tosylated compound. This tosylated compound is further reaction with sodium methoxide which undergoes again SN2 type of reaction, the methoxide ion attacks the carbon atom through the back side and provides Inverse configuration of methoxy compound. This is shown below,
SN2 reaction is second order reaction, the rate of the reaction is depending on the both substrate and nucleophiles.
![Check Mark](/static/check-mark.png)
Answer to Problem 45AP
The reaction is given below,
Explanation of Solution
Given information:
The reaction is given below,
The reaction is given below,
Ethyl bromide undergoes nucleophilic substitution reaction with cyanide (sodium cyanide) gives the corresponding cyanide product, this cyanide undergoes catalytic reduction using Pt (metal reduction) gives
The given molecule is prepared by using nucleophilic substitution reaction.
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Chapter 11 Solutions
OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card for McMurry's Organic Chemistry, 9th
- Dr. Mendel asked his BIOL 260 class what their height was and what their parent's heights were. He plotted that data in the graph below to determine if height was a heritable trait. A. Is height a heritable trait? If yes, what is the heritability value? (2 pts) B. If the phenotypic variation is 30, what is the variation due to additive alleles? (2 pts) Offspring Height (Inches) 75 67.5 60 52.5 y = 0.9264x + 4.8519 55 60 65 MidParent Height (Inches) 70 75 12pt v V Paragraph B IUA > AT2 v Varrow_forwardExperiment: Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below. Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization. Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C Sample C-Cool the third sample in an ice-bath to 0-2 °C Results: weight after recrystalization and melting point temp. A=0.624g,102-115° B=0.765g, 80-105° C=1.135g, 77-108 What is the percent yield of A,B, and C.arrow_forwardRel. Intensity Q 1. Which one of the following is true of the compound whose mass spectrum is shown here? Explain how you decided. 100 a) It contains chlorine. b) It contains bromine. c) It contains neither chlorine nor bromine. 80- 60- 40- 20- 0.0 0.0 TT 40 80 120 160 m/z 2. Using the Table of IR Absorptions how could you distinguish between these two compounds in the IR? What absorbance would one compound have that the other compound does not? HO CIarrow_forward
- Illustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forwardDraw the following molecule: (Z)-1-chloro-1-butenearrow_forwardIdentify the molecule as having a(n) E, Z, cis, or trans configuration. CH3 H₁₂C ○ E ○ z ○ cis transarrow_forward
- Identify the molecule as having a(n) E, Z, cis, or trans configuration. H₂C- CH3 О Е ○ cis ○ transarrow_forwardThe decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forwardDon't used hand raitingarrow_forward
- CS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?arrow_forwardCS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forwardThe following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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