Q: Draw the two products of the reaction. H₂C. CH₂ H :0: CH3 CH₂ +1
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Write the mechanism for the reaction.
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- HNO3 d= H* Br f.Answer questions 1 and 2 according to the data given. Dater Weight of cream i: 326 kỳ. Table shows some data obtained directly from Lactascan instrument. Fat % SNF % Lacto- density 27.32 30.23 Raw milk 4.15 7.97 Skim milk 0.08 8.26 Q1. Calculate fat percent of creamn A) 46 B) 28 (C) 3D D) 0.046 آدرما 396 100 x Q2. Calculate efficiency of the cream separator. A) 100% B98% C) 97% D) 96% E) 87.2% amount 2500 L E) 0.28CI + а. (еxcess) H30* H С. H20 ОН b.
- (c) 1. THF H2C CEN 7. 2. H30* N(CH312 (d) 1. THF N' 2. H3O* 2016 Cmn LaungPart D: Food Calories Naked Juice Serving size 240 mL D1. Name of food product D2. Mass of food nutrients in one serving Fat Carbohydrate 33 g, Protein g, D3. Calculations for Calories (Cal) or kilocalories (kcal) per serving kcal (Cal) Carbohydrate Protein kcal (Cal) Fat kcal (Cal) D4. Total Calories (Cal or kcal) per serving kcal (Cal) D5. Calories (for one serving) listed on the label cal (Cal) D6. Percentage of total Calories from carbohydrate % (show calculations) D7. Percentage of total Calories from protein (show calculations) % D8. Percentage of total Calories from fat (show calculations) % Q 4. How does your calculated number of Calories in one serving compare to the Calories listed on the food product nutrition label? Comment on it.-|· 4.0 H3C 3.0 Match the peaks in this spectrum with hydrogens on the structure below. A) I: 0.91 ppm II: 3.29 ppm III: 1.52 ppm IV: 3.23 ppm H₂ CH3 CH 2.0 CH3 IV ppm 1.0 B) I: 0.91 ppm II: 3.29 ppm III: 3.23 ppm IV: 1.52 ppm C) 1: 3.23 ppm II: 3.29 ppm
- Convert 200C into K+ e Home ourse.html?courseld=15539865&HepID=676f177415469ec3dc78ff3c8 bf724d9#1 0001 Inbox-Outlook We... S Sugarpill Cosmetic... Shop | Origami Owl Wholesale Glass M... S The Corinthian Hou... zed Invitat... HW Provide Feedback P Pearson Contact Us Copyright 2019 Pearson Education Inc. All rights reserved. Terms of Use Privacy Policy | Permissions MacBook Air »)) DD DII O00 F12 F11 F10 F9 F8 F7 F4 F6 F5 F3 + $ & 3 0 9 4 7 8 6 5 } { P E U R Y D L K G F H T 2LOCH₂-COOH Citric acid has the formula HO-C-COOH I CH₂-COOH CH2–CDD - Na* + HD-C-CDD- Na CH₂-COO- COO-Na A 25.0 mL sample of a concentrated citrus fruit cordial component (e.g. for lime juice), used in the food & drinks industry, was diluted to 250 mL in a graduated volumetric flask. A 25.0 mL sample of this diluted solution, required, on average, 22.5 mL of a standard 0.100 molar sodium hydroxide solution using phenolphthalein indicator for the titration end-point. A) 0.0075 Assuming all the acid in the cordial was citric acid, calculate the concentration of the acid in g/mL in the original solution. B) 0.576 D and is tribasic acid, forming the tri-sodium salt on complete neutralisation with sodium hydroxide. 1.44 0.00225
- Convert 45 mi/h to m/s, showing how the units cancel appropriately.il VHL Central | Dashboard X Consider the following data. Louisiana State University webassign.net web/Student/Assignment-Responses/last?dep=29518359#question308437_16 YouTube U FX - USTVGO.TV = 1.1 Chemistry in Co... AH = 2 NO(g) N₂(g) + O₂(g) 2 NO₂(g) 2 NO(g) + O₂(g) 2 N₂(g) + O₂(g) = 2 N₂O(g) Use Hess's law to calculate AH for the reaction below. KJ X 2022 Fall MATH 1100 for E X y! ml to I - Yahoo Search Res X Psychology 2e ΔΗ = -180.7 kJ ΔΗ = +113.1 kJ ΔΗ = +163.2 kJ Watch Black Clover... VHL Central | Dash... 3 NO(g) N₂O(g) + NO₂(g)Convert -40. kcal/mol to kJ/mol using the fact that 1kcal = 4.184 kJ. Show work using dimensional analysis. kcal 1 kcal 4.184 kJ kJ = -9.6 mol a. -40. mol -40. kcal mol Ob. 4.184 kJ 1 kcal kJ = -170 mol Once we know the value of AHrxn it is possible to solve many other types of problems. For example, how many moles of zinc should we react with 6HCI to generate 120 kJ of heat? О а. 120 kJ 1 mol = 0.71 mol -170 kJ O b. 120 kJ|-170 kJ 20,000 mol 1 mol How many grams of zinc react with excess 6M HCI if 500. kJ of heat are released? Use dimensional analysis, the AHrxn and the atomic mass of zinc. O a. 500. kJ 1 mol 65.39 g = 190 g Zn -170 kJ 1 mol O b. 500. kJ 1 mol 1 mol
