CHA a) II, I, III, IV, V b) II, III, I, V, IV 15. Put the following compounds in the order of increasing acidity (least first). H₂O NH3 1pKa=51 11pka = 38 111 pKa=15.7 IV. HCI HF Pka= = 3.2 Vp8a=-7 c) I, III, II, V, IV d), II, III, IV, V 16. The correct sequence of the ions shown, in order of increasing basicity, is: A) CH3CH2: < B) CH3CH2: C) HC=C: D) CH2=CH: E) HC=C: < CH2=CH: HC=C: < < HC=C: CH2=CH: CH3CH2: < CH2=CH: < HC=C: < CH3CH2:1 < CH2=CH:" < CH3CH2: Hybridization 3 Sp> sp²> sp³. H-C = C= SP H H Sp² Carbanion hybridization H-C-C-H H = Sp Sp2 Sp³ most stable least stable carbcation hybridization SP 502 Sp3 least table 6 most Stable 一工 Sp3 ल

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ISBN:9781305080485
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Chapter20: Carboxylic Acids And Nitriles
Section20.3: Biological Acids And The Henderson–hasselbalch Equation
Problem 5P: Calculate the percentages of dissociated and undissociated forms present in the following solutions:...
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(SE EX 2) Problems 15-16, can you please explain them to me in detail and color-code anything if necessary?

CHA
a) II, I, III, IV, V
b) II, III, I, V, IV
15. Put the following compounds in the order of increasing acidity (least first).
H₂O
NH3
1pKa=51 11pka = 38 111 pKa=15.7 IV.
HCI
HF
Pka=
= 3.2
Vp8a=-7
c) I, III, II, V, IV
d), II, III, IV, V
16.
The correct sequence of the ions shown, in order of increasing
basicity, is:
A) CH3CH2: <
B) CH3CH2:
C) HC=C:
D) CH2=CH:
E) HC=C:
<
CH2=CH:
HC=C:
<
<
HC=C:
CH2=CH:
CH3CH2:
<
CH2=CH:
< HC=C:
<
CH3CH2:1
<
CH2=CH:"
< CH3CH2:
Hybridization
3
Sp> sp²> sp³.
H-C = C=
SP
H
H
Sp²
Carbanion hybridization
H-C-C-H
H
=
Sp
Sp2
Sp³
most stable
least stable
carbcation hybridization
SP
502
Sp3
least table
6 most
Stable
一工
Sp3
ल
Transcribed Image Text:CHA a) II, I, III, IV, V b) II, III, I, V, IV 15. Put the following compounds in the order of increasing acidity (least first). H₂O NH3 1pKa=51 11pka = 38 111 pKa=15.7 IV. HCI HF Pka= = 3.2 Vp8a=-7 c) I, III, II, V, IV d), II, III, IV, V 16. The correct sequence of the ions shown, in order of increasing basicity, is: A) CH3CH2: < B) CH3CH2: C) HC=C: D) CH2=CH: E) HC=C: < CH2=CH: HC=C: < < HC=C: CH2=CH: CH3CH2: < CH2=CH: < HC=C: < CH3CH2:1 < CH2=CH:" < CH3CH2: Hybridization 3 Sp> sp²> sp³. H-C = C= SP H H Sp² Carbanion hybridization H-C-C-H H = Sp Sp2 Sp³ most stable least stable carbcation hybridization SP 502 Sp3 least table 6 most Stable 一工 Sp3 ल
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