Interpretation:
The reagent used to accomplish the given transformation has to be identified.
Concept Introduction:
Elimination reactions are the one in which the groups are lost and the saturated bonds are converted to unsaturated bonds. Usually the substitution reaction compete with elimination reaction.
In elimination reaction, the beta proton is removed together with the leaving group to form a double bond.
E2 reaction proceeds through a single step without any formation of intermediates. The base abstracts a proton form the substrate and the loss of leaving group also happens resulting in the formation of double bond. E2 stands for bimolecular elimination.
The proton can be abstracted by the base in two different ways leading to a regiochemical outcome. In the given reaction below, two
The two alkenes that are formed can be given different names. If the alkene is more substituted means it is known as Zaitsev product, and if the alkene formed is less substituted means it is known as Hofmann product. Generally more substituted product is the major product (Zaitsev product).
If the reaction is performed with a sterically hindered base, the major product will be less substituted alkene (Hofmann product). The regiochemical outcome can be decided by choosing the base. Some of the sterically hindered bases are,
Addition reactions are the one in which the groups are added to an unsaturated double bond. The double bond is destroyed because the groups are added across the double bond. If the considered alkene is a symmetrical one, then there is no difference in the product obtained but if the alkene is an unsymmetrical one, then regiochemistry decides the products that are obtained.
When two similar groups are added across a double bond, regiochemistry is irrelevant. When adding two different groups across the double bond of an unsymmetrical alkene, the regiochemistry becomes relevant. In simple words, it can be said that, when two different groups are added across a double bond, then regiochemistry becomes relevant.
Markovnikov Addition
In the vinylic bond, if the bulky group gets substituted in the carbon atom that is more substituted means, it is known as Markovnikov’s addition.
anti-Markovnikov Addition
In the vinylic bond, if the bulky group gets substituted in the carbon atom that is less substituted means, it is known as anti-Markovnikov’s addition.

Want to see the full answer?
Check out a sample textbook solution
Chapter 11 Solutions
ORGANIC CHEMISTRY-NEXTGEN+BOX (1 SEM.)
- Synthesize 2-Ethyl-3-methyloxirane from dimethyl(propyl)sulfonium iodide using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardSynthesize 2-Hydroxy-2-phenylacetonitrile from phenylmethanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardSynthesize N-Methylcyclohexylamine from cyclohexanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forward
- Synthesize N-Methylcyclohexylamine from cyclohexanol using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forwardIf possible, please provide the formula of the compound 3,3-dimethylbut-2-enal.arrow_forwardSynthesize 1,4-dibromobenzene from acetanilide (N-phenylacetamide) using the necessary organic or inorganic reagents. Draw the structures of the compounds.arrow_forward
- Indicate the products obtained by mixing (3-oxo-3-phenylpropyl)triphenylphosphonium bromide with sodium hydride.arrow_forwardWe mix N-ethyl-2-hexanamine with excess methyl iodide and followed by heating with aqueous Ag2O. Indicate the major products obtained.arrow_forwardIndicate the products obtained by mixing acetophenone with iodine and NaOH.arrow_forward
- Indicate the products obtained by mixing 2-Propanone and ethyllithium and performing a subsequent acid hydrolysis.arrow_forwardIndicate the products obtained if (E)-2-butenal and 3-oxo-butanenitrile are mixed with sodium ethoxide in ethanol.arrow_forwardQuestion 3 (4 points), Draw a full arrow-pushing mechanism for the following reaction Please draw all structures clearly. Note that this intramolecular cyclization is analogous to the mechanism for halohydrin formation. COH Br + HBr Brarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





