Chapter 11.6, Problem 67AYU

To determine

To graph: Each equation and find points of intersection.

Answer to Problem 67AYU

Explanation of Solution

Given:

${\left(x - 1\right)}^2 + {\left(y + 2\right)}^2 = 4$    -----(Eq 1)

$y^2 + 4y - x + 1 = 0$    -----(Eq 2)

Graph:

It can be seen from the graph that the curves intersect at $(1,0)$, $(1,\text{-}4)$, $(0,\text{-}0.27)$ and $(0,\text{-}3.73)$.