Chapter 11, Problem 7RE

To determine

To solve: each system of the given equations using substitution or elimination.

Answer to Problem 7RE

Solution: $(\frac{11}{5},\frac{5}{3})$

Explanation of Solution

  $\{\begin{array}{l}y=2x-5\\ x=3y+4\end{array}$

Substitute the expression of $y$ from first into the second equation

  $\begin{array}{l}x=3(2x-5)+4\\ x=6x-15+4\\ 5x=11\\ x=\frac{11}{5}\end{array}$

Solve for $y$

  $\begin{array}{l}y=2.\frac{11}{5}-5\\ y=-\frac{3}{5}\end{array}$