Chapter 11.1, Problem 31AYU

To determine

To find: The solution of the given system of equations.

Answer to Problem 31AYU

$x=1,y=1$

Explanation of Solution

Given:

$2x-3y=-1$

$10x+y=11$

Calculation:

The system of equations is:

$2x-3y=-1$

$10x+y=11$

Multiplying the second equation by 3 and adding with the first equation we get,

$\left(2x-3y\right)+3\left(10x+y\right)=-1+3\left(11\right)$

$2x-3y+30x+3y=-1+33$

$32x=32$

$x=\frac{32}{32}$

$x=1$

Substituting $x=1$ in the first equation we get,

$2\left(1\right)-3y=-1$

$2-3y=-1$

$-3y=-1-2$

$-3y=-3$

$y=\frac{-3}{-3}$

$y=1$

Thus $x=1,y=1$ is the solution of the given system of equations.