To find: The dimensions of a rectangular field if the difference between its length and width is 50 meters and the length of fence required to enclose the field is 3000 meters.
Answer to Problem 56AYU
.
Explanation of Solution
Given:
Difference between the length and width of the rectangular field is 50 meters.
Length of fence to enclose the field .
Calculation:
Let the width of the rectangular field be meters.
Then the length of the field is meters.
Length of fence to enclose the field Perimeter of the rectangular field .
We know that in a rectangle,
Thus we get,
Therefore the width of the rectangular field is 725 meters.
Then the length of the rectangular field becomes meters.
Hence the dimensions, that is, the length and width of the rectangular field are 775 meters and 725 meters respectively.
Chapter 11 Solutions
Precalculus
Additional Math Textbook Solutions
Precalculus
Calculus: Early Transcendentals (3rd Edition)
Glencoe Math Accelerated, Student Edition
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
University Calculus: Early Transcendentals (3rd Edition)
Calculus & Its Applications (14th Edition)
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning