Chapter 11.4, Problem 30PPS

To determine

Determine the most likely number of successes.

Answer to Problem 30PPS

  $\boxed{4}$

Explanation of Solution

Given information:

Each binomial distribution has $n$ trials and $p$ probability of success. Determine the most likely number of successes.

  $n=10,p=0.4$

Calculation:

Put the following attributes for a binomial distribution:

  $n=10,p=0.4$

Generally, the mean $\mu$ or the most likely number of successes, of any binomial distribution is, $\mu =np$

Here $n$ is the number of trials and $p$ is the probability of success.

Substitute $n=10,p=0.4$ in the above formula to find the most likely number of successes,

  $\mu =np$

  $\begin{array}{l}=10(0.4)\\ =4\end{array}$

Hence, the most likely number of successes is $\boxed{4}$ .