Chapter 11.3, Problem 2Q

To determine

To find the mean, median and mode of data set.

Answer to Problem 2Q

Mean $=1314.88$

Median = $1191$

Mode = $1000$

Explanation of Solution

Given information: $1000,1267,1328,1200,1180,1000,2568,1191,1100$

Formula Used: Mean = $\frac{Sumofallobservations}{Totalobservations}$ , Median = ${\left(\frac{n+1}{2}\right)}^{th}term$ , Mode = Most repeated value.

Calculation:

  $1000,1267,1328,1200,1180,1000,2568,1191,1100$

Now, in Ascending Order

  $1000,1000,1100,1180,1191,1200,1267,1328,2568$

• Mean

Mean = $\frac{Sumofallobservations}{Totalobservations}$

So,

Mean = $\frac{1000+1000+1100+1180+1191+1200+1267+1328+2568}{9}$

Now,

Mean = $\frac{11834}{9}$

Hence,

Mean $=1314.88$

• Median

Median = ${\left(\frac{n+1}{2}\right)}^{th}term$

So,

Median = ${\left(\frac{9+1}{2}\right)}^{th}term$

Now,

Median = $5^{th}term$

Hence,

Median = $1191$

• Mode

Mode = Most repeated value.

So,

  $1000$ Is the most repeated value.

Mode = $1000$

Median best describes the central tendency of the data because the outlier disturbs the mean.