Chapter 11.2, Problem 15E

(a)

To determine

To find the range of data.

Answer to Problem 15E

Range = $9.5$

Explanation of Solution

Given information: Box-and-whisker plot.

Formula Used: Range of the data= $max.-\min .$

Calculation:

  

As the range of the data: $max.-\min .$

So,

Range = $18.25-8.75$

Hence,

Range = $9.5$

(b)

To determine

To describe the distribution of data.

Answer to Problem 15E

Positively Skewed

Explanation of Solution

Given information: Box-and-whisker plot.

Calculation:

  

The distribution is positively skewed as the mean typically gets pulled toward the tail, and is greater than the median.

(c)

To determine

To find the interquartile range of data.

Answer to Problem 15E

Interquartile Range = $4.25$

Explanation of Solution

Given information: Box-and-whisker plot.

Formula Used: Interquartile range of the data = $Q_3-Q_1$

Calculation:

  

As the Interquartile range of the data = $Q_3-Q_1$

So,

Interquartile Range = $14.75-10.5$

Hence,

Interquartile Range = $4.25$

(D)

To determine

To describe the data more spread out.

Answer to Problem 15E

Yes

Explanation of Solution

Given information: Box-and-whisker plot.

Calculation:

  

Yes, the data is more spread out.

Because range of the data is much greater than interquartile range.