(a)
Interpretation:
The balanced chemical equation for given reaction is to be stated.
Concept introduction:
A balanced chemical equation consists of equal number of atoms of all the elements that are present in a
(a)

Answer to Problem 24PP
The balanced chemical equation for given reaction is shown below:
Explanation of Solution
The reactants are carbon dioxide and water and the reaction leads to the formation of glucose and oxygen. The chemical equation corresponding to given reaction is shown below:
(b)
Interpretation:
The limiting reagent in given reaction is to be determined.
Concept introduction:
The formula to calculate the number of moles is given as shown below:
(b)

Answer to Problem 24PP
Carbon dioxide acts as the limiting reagent.
Explanation of Solution
The molar mass of carbon dioxide is
The molar mass of water is
The limiting reagent is determined as shown below:
Thus, the given amount of water is more than required. Therefore, carbon dioxide acts as the limiting reagent.
(c)
Interpretation:
The excess reagent in given reaction is to be determined.
Concept introduction:
The reagent that gets completely used in reaction is the limiting reagent. The reagent that is left even after the reaction is defined as the excess reagent.
(c)

Answer to Problem 24PP
Water acts as the excess reagent.
Explanation of Solution
The given moles of water are
(d)
Interpretation:
The mass of excess reagent is to be stated.
Concept introduction:
The reagent that gets completely used in reaction is the limiting reagent. The reagent that is left even after the reaction is defined as the excess reagent.
(d)

Answer to Problem 24PP
The mass of excess reagent is
Explanation of Solution
The given moles of water are
(e)
Interpretation:
The mass of glucose formed is to be stated.
Concept introduction:
The reagent that gets completely used in reaction is the limiting reagent. The reagent that is left even after the reaction is defined as the excess reagent.
(e)

Answer to Problem 24PP
The mass of glucose formed is
Explanation of Solution
The moles of glucose formed are calculated as shown below:
The molar mass of glucose is
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