(a)
Interpretation:
A chemical equation is given. It has to be balanced and interpreted in terms of particles, moles and mass and obeying of law of conservation of mass in it has to be shown.
Concept introduction:
According to law of conservation of mass it is not possible to form the mass or to destroy the mass. The mass always remains conserved.
The number of moles is calculated as shown below.
(a)

Answer to Problem 2PP
In the given equation shows that two molecules of sodium reacts with two molecules of water to form two molecules of sodium hydroxide and one molecule of hydrogen gas. In terms of number of moles it is seen that two moles of sodium reacts with two moles of water gas to form two moles of sodium hydroxide and one mole of hydrogen gas. Here,
The law of conservation of mass is obeyed by the given chemical equation.
Explanation of Solution
The given chemical equation is shown below.
The coefficient of two is multiplied with sodium, water and sodium hydroxide to balance the chemical equation.
The above equation shows that two molecules of sodium reacts with two molecules of water to form two molecules of sodium hydroxide and one molecule of hydrogen gas. In terms of number of moles it is seen that two moles of sodium reacts with two moles of water gas to form two moles of sodium hydroxide and one mole of hydrogen gas.
The molar mass of sodium is
The molar mass of water is
The molar mass of sodium hydroxide is
The molar mass of hydrogen is
Thus,
Total mass of reactants and products is given as shown below.
Here, the mass of reactants is equal to mass of the products. Thus, law of conservation of mass is obeyed.
(b)
Interpretation:
A chemical equation is given. It has to be balanced and interpreted in terms of particles, moles and mass and obeying of law of conservation of mass in it has to be shown.
Concept introduction:
According to law of conservation of mass it is not possible to form the mass or to destroy the mass. The mass always remains conserved.
The number of moles is calculated as shown below.
(b)

Answer to Problem 2PP
In the given equation shows that four molecules of zinc reacts with ten molecules of nitric acid to form four molecules of zinc nitrate, one molecule of nitrous oxide and five molecules of water. In terms of number of moles it is seen that four moles of zinc reacts with ten moles of nitric acid to form four moles of zinc nitrate, one mole of nitrous oxide and five moles of water. Here,
The law of conservation of mass is obeyed by the given chemical equation.
Explanation of Solution
The given chemical equation is shown below.
The coefficient of four is multiplied with zinc, ten with nitric acid, four with zinc nitrate and five with water to balance the given chemical equation.
The above equation shows that four molecules of zinc reacts with ten molecules of nitric acid to form four molecules of zinc nitrate, one molecule of nitrous oxide and five molecules of water. In terms of number of moles it is seen that four moles of zinc reacts with ten moles of nitric acid to form four moles of zinc nitrate, one mole of nitrous oxide and five moles of water.
The molar mass of zinc is
The molar mass of nitric acid is
The molar mass of zinc nitrate is
The molar mass of nitrous oxide is
The molar mass of water is
Thus,
Total mass of reactants and products is given as shown below.
Here, the mass of reactants is equal to mass of the products. Thus, law of conservation of mass is obeyed.
Chapter 11 Solutions
Chemistry: Matter and Change
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