(a) Explanation Given information: The initial velocity ( v 0 ) A of the rocket A is 100 m/s . The height ( y A ) of rocket A falling is 300 m . The constant acceleration ( g ) is 9.81 m/s 2 . Calculation: Write the equation of motion for rocket A ( y A ) : y A = ( y 0 ) A + ( v 0 ) A t − 1 2 g t 2 Here, ( y 0 ) A is initial position of rocket A , ( v 0 ) A is initial speed of rocket A , t is time required for acceleration. Substitute 100 m / s for ( v 0 ) A , zero for ( y 0 ) A , and 9.81 m / s 2 for g y B = 0 + 100 t − 1 2 ( 9.81 ) t 2 = 100 t − 4.905 t 2 (1) Write the equation of motion for rocket B ( y B ) : y B = ( y 0 ) B + ( v 0 ) B ( t − t 1 ) − 1 2 g ( t − t 1 ) 2 Here, ( y 0 ) B is initial position of rocket B and ( v 0 ) B is initial speed of rocket B . Substitute 100 m / s for ( v 0 ) B , 0 for ( y 0 ) B , and 9 (b) To determine The velocity of B relative to A ( v B / A ) at the time of the explosion.

Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9780073398242

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 11.2, Problem 11.45P

(a)

To determine

The time (t1).

(b)

To determine

The velocity of B relative to A (vB/A) at the time of the explosion.

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Chapter 11.2, Problem 11.44P

Chapter 11.2, Problem 11.46P

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The time ( t 1 ) .