(a) Explanation Given information: The constant acceleration ( a B ) of block B is 6 in ./s 2 . The constant velocity ( v B ) of block B is 3 in./s. Calculation: Show the free body diagram of the block as in Figure (1). Write the equation for total lengths of cables. L 1 = 2 y C + 2 y D +constant (1) L 2 = y A + y B + ( y B − y D ) +constant Multiply the Equation by 2. 2 L 2 = 2 y A + 2 y B + 2 ( y B − y D ) +constant (2) Add Equation (1) and (2). L 1 + 2 L 2 = 2 y C + 2 y D + 2 y A + 2 y B +2 ( y B − y D ) + constant 2 ( y C + y A + 2 y B ) = constant Differentiate the Equation to obtain the relationships for velocities and accelerations. v C + v A + 2 v B = 0 (3) a C + a A + 2 a B = 0 (4) Write the equation for motion of block A . Δ y A = 1 2 a A t 2 Substitute 6 in ./s 2 for a A . Δ y A = 1 2 × 6 × t 2 = 3 t 2 Write the equation for motion of block B (b) To determine The position ( Δ y C ) of the block C .

Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9780073398242

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

See similar textbooks

Concept explainers

Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be create…

Videos

Question

Chapter 11.2, Problem 11.56P

(a)

To determine

The time when the velocity of block C is zero.

(b)

To determine

The position (ΔyC) of the block C.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 11.2, Problem 11.55P

Chapter 11.2, Problem 11.57P

Students have asked these similar questions

How do you find these answers?

250 mm 400 mm A B C E F 250 mm PROBLEM 1.52 Each of the two vertical links CF connecting the two horizontal members AD and EG has a 10 × 40-mm uniform rectangular cross section and is made of a steel with an ultimate strength in tension of 400 MPa, while each of the pins at C and F has a 20-mm diameter and are made of a steel with an ultimate strength in shear of 150 MPa. Determine the overall factor of safety for the links CF and the pins connecting them to the horizontal members. 24 kN

50 mm 12 mm B O C OA 300 mm 450 mm E PROBLEM 1.51 Each of the steel links AB and CD is connected to a support and to member BCE by 25-mm-diameter steel pins acting in single shear. Knowing that the ultimate shearing stress is 210 MPa for the steel used in the pins and that the ultimate normal stress is 490 MPa for the steel used in the links, determine the allowable load P if an overall factor of safety of 3.0 is desired. (Note that the links are not reinforced around the pin holes.)

Chapter 11 Solutions

Vector Mechanics for Engineers: Statics and Dynamics

Ch. 11.1 - A bus travels the 100 miles between A and B at 50...Ch. 11.1 - Two cars A and B race each other down a straight...Ch. 11.1 - A snowboarder starts from rest at the top of a...Ch. 11.1 - Prob. 11.2P Ch. 11.1 - Prob. 11.3P Ch. 11.1 - A loaded railroad car is rolling at a constant...Ch. 11.1 - Prob. 11.5P Ch. 11.1 - Prob. 11.6P Ch. 11.1 - A girl operates a radio-controlled model car in a...Ch. 11.1 - The motion of a particle is defined by the...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.