Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
8th Edition
ISBN: 9780073398174
Author: Yunus A. Cengel Dr., Michael A. Boles
Publisher: McGraw-Hill Education
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Chapter 1.11, Problem 57P
To determine

Express the gage pressure and absolute pressures in kPa, kN/m2, lbf/in.2, psi and mmHg.

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Answer to Problem 57P

The absolute pressures in kPa,kN/m2, lbf/in.2, psi and mmHg are 18kPa, 18kN/m2, 2.61lbf/in.2,2.61psi and 135mmHg respectively.

Explanation of Solution

Write the formula to calculate the gage pressure (Pgage).

Pgage=PabsPatm(for pressures abovePatm)

Here, absolute pressure is Pabs and atmospheric pressure is Patm.

Write the formula to calculate the absolute pressure (Pabs).

Pabs=PatmPvac(for pressures belowPatm) (I)

Here, vacuum pressure is Pvac.

Write the expression of conversion relation for the pressure from kPa to kN/m2.

P(kPa)=P(kPa)×1kN/m21kPa=P(kN/m2)

Write the expression of conversion relation for the pressure from kPa to lbf/in.2.

P(kPa)=P(kPa)×1lbf/in.26.895kPa=P(lbf/in.2)

Write the expression of conversion relation for the pressure from kPa to psi.

P(kPa)=P(kPa)×1psi6.895kPa=P(psi)

Write the expression of conversion relation for the pressure from kPa to mmHg.

P(kPa)=P(kPa)×1mmHg0.1333kPa=P(mmHg)

Conclusion:

The gage pressure cannot be found for the pressures below the atmospheric pressure.

Substitute 98kPa for Patm and 80kPa for Pvac in Equation (I).

Pabs=98kPa80kPa=18kPa

Convert the unit of pressure from kPa to kN/m2.

Pabs=18kPa=18kPa×1kN/m21kPa=18kN/m2

Convert the unit of pressure from kPa to lbf/in.2.

Pabs=18kPa=18kPa×1lbf/in.26.895kPa=2.61lbf/in.2

Convert the unit of pressure from kPa to psi.

Pabs=18kPa=18kPa×1psi6.895kPa=2.61psi

Convert the unit of pressure from kPa to mmHg.

Pabs=18kPa=18kPa×1mmHg0.1333kPa=135mmHg

Thus, the absolute pressures in kPa,kN/m2, lbf/in.2, psi and mmHg are 18kPa, 18kN/m2, 2.61lbf/in.2,2.61psi and 135mmHg respectively.

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Chapter 1 Solutions

Thermodynamics: An Engineering Approach

Ch. 1.11 - Prob. 11PCh. 1.11 - Prob. 12PCh. 1.11 - Solve Prob. 113 using appropriate software. Print...Ch. 1.11 - A 4-kW resistance heater in a water heater runs...Ch. 1.11 - A 150-lbm astronaut took his bathroom scale (a...Ch. 1.11 - The gas tank of a car is filled with a nozzle that...Ch. 1.11 - Prob. 17PCh. 1.11 - A large fraction of the thermal energy generated...Ch. 1.11 - Prob. 19PCh. 1.11 - 1–20C A can or soft drink at room temperature is...Ch. 1.11 - What is the difference between intensive and...Ch. 1.11 - Is the number of moles of a substance contained in...Ch. 1.11 - Is the state of the air in an isolated room...Ch. 1.11 - The specific weight of a system is defined as the...Ch. 1.11 - What is a quasi-equilibrium process? What is its...Ch. 1.11 - Define the isothermal, isobaric, and isochoric...Ch. 1.11 - Prob. 27PCh. 1.11 - Prob. 28PCh. 1.11 - 1–29C What is specific gravity? 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